Hi there,
I´m using IML/SAS in SAS Enterprise Guide.
Is there any solution that allows us to obtain Matrix B after apply retained minimization on Matrix A by row (see below)?
Thank you very much!
Use the elementwise minimum operator (><) as explained in this blog post:
proc iml;
A ={
94 19 89 73 78 33 87 73 8 85 80 43 0,
92 95 69 64 32 11 30 18 11 75 82 48 99,
34 92 58 80 24 68 34 98 87 41 18 34 5};
B = A;
do j = 2 to ncol(A);
B[,j] = (B[,j-1] >< B[,j]);
end;
print B;
Use the elementwise minimum operator (><) as explained in this blog post:
proc iml;
A ={
94 19 89 73 78 33 87 73 8 85 80 43 0,
92 95 69 64 32 11 30 18 11 75 82 48 99,
34 92 58 80 24 68 34 98 87 41 18 34 5};
B = A;
do j = 2 to ncol(A);
B[,j] = (B[,j-1] >< B[,j]);
end;
print B;
Thank you Rick_SAS. That's all I need
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