Statistical programming, matrix languages, and more

How do I output a randon number within an interval in proc iml

Reply
Super Contributor
Posts: 270

How do I output a randon number within an interval in proc iml

Hello Ladies and Gentlemen,

I am trying to output a random number within a proc iml statement.

For example if i do: A=RANUNI(-1); any time it give a different random number between 0 and 1.

Now I have my interval (Bi, Bi+1) and I want a random number between this interval. Just like RANUNI(-1), I want this interval to change anytime I run it and to vary as I vary my interval

SAS Super FREQ
Posts: 3,221

Re: How do I output a randon number within an interval in proc iml

See the article How to generate random numbers in SAS - The DO Loop which shows how to use the RANDGEN routine to generate random numbers.  If u is in the inerval [0,1] then Bi+u is in the interval you want.   You can use CALL RANDSEED(0) if you want the random number stream to be different each time you run the program.  Remember also that if you are going to need thousands of random numbers to vectorize the program by allocating an array and filling it: Efficient Sampling - The DO Loop

Super Contributor
Posts: 270

Re: How do I output a randon number within an interval in proc iml

My  interval varies and it is  like (0.93, 1.41) and I want a random a within the the interval. THe other interval is (0.67,0.83)

Regular Contributor
Posts: 152

Re: How do I output a randon number within an interval in proc iml

If the uniform random number you generate equals RN, the random value within a specific interval from LOW to HIGH equals:

      Random value = LOW + RN*(HIGH - LOW).

Super Contributor
Posts: 270

Re: How do I output a randon number within an interval in proc iml

Thanks answered

Post a Question
Discussion Stats
  • 4 replies
  • 310 views
  • 0 likes
  • 3 in conversation