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kindernet
Fluorite | Level 6

Hello, I am new to SAS and have a problem using the SAS/IML.

When I use the following code, it shows the following error. The code is from a textbook I use to create a word matrix, but I get an error message and blank matrix.

Can anybody give me some suggestions for this problem?

Thank you. 

libname d'/folders/myfolders/song';
options ps=500 ls=132;
data worddata;
infile '/folders/myfolders/song/70songs.txt' delimiter='';
input word: $20. @@;
LW=length(word);
check=substr(word,LW,1);

data voclist;
infile "/folders/myfolders/song/voclist.txt";
input voc $;

proc iml; reset fw=5;
workspace=30000;
use worddata;
read all var {word} into w;
read all var {check} into c;
use voclist;
read all var _char_ into v;
w=concat(w,c);
d=j(nrow(v),nrow(v),0);
LW=length(w);

tagi=0;tagj=0;

check=substr(w,LW,1);

do i=1 to nrow(v);
vis=v(|i,1|);
do j=1 to nrow(v);
vjs=v(|j,1|);
L1=length(vis);
LJ=length(vjs);
k=1; ti=0; tj=0;
jf=j(nrow(w),1,0);

loop: do position = k to (nrow(w)-1) until (check(|position,1|)="#");
wsi=substr(w(|position,1|),1,LI);
wsj=substr(w(|position,1|),1,LJ);

if v(|i,l|)=wsi then do;
tagi=tagi+1; ti=ti+1; end;
if v(|j,1|)=wsj then do;
tagj=tagj+1; tj=tj+1; end;
end;
jf[position,1]=min(ti,tj);
k=position+1; ti=0; tj=0;

if position<nrow(w) then goto loop;

s=sum(jf);
d[i,j]=d(|i,j|)+s;
end;
end;

print d;

create d.network from d;
append from d;
quit;

Error message:

ERROR: (execution) Matrix has not been set to a value

 

Log:

...

126 end;
ERROR: (execution) Matrix has not been set to a value.

operation : SUBSTR at line 110 column 11
operands : _TEM1001, *LIT1022, LI

_TEM1001 1 row 1 col (character, size 40)

가는 �

*LIT1022 1 row 1 col (numeric)

1

LI 0 row 0 col (type ?, size 0)


statement : ASSIGN at line 110 column 1
127
128 print d;
129
130 create d.network from d;
131 append from d;
132 quit;

1 ACCEPTED SOLUTION

Accepted Solutions
IanWakeling
Barite | Level 11

I think the problem is a simple typo.  The line :

L1=length(vis);

uses the number '1' in the variable name instead of the letter 'I'.  Then the error that you have shown occurs at the line,

wsi=substr(w(|position,1|),1,LI);

as the 3rd agrument to the substr() function does not exist.

View solution in original post

5 REPLIES 5
IanWakeling
Barite | Level 11

I think the problem is a simple typo.  The line :

L1=length(vis);

uses the number '1' in the variable name instead of the letter 'I'.  Then the error that you have shown occurs at the line,

wsi=substr(w(|position,1|),1,LI);

as the 3rd agrument to the substr() function does not exist.

kindernet
Fluorite | Level 6

Thank you very much for the quick response.

I changed the code as you commented, and was able to run the code.

-Actually, I had another error with the same typo(1/l) you commented, and also had to fix it.

if v(|i,1|)=wsi then do;

 I am still learning to use SAS, so I really appreciate your help.

Rick_SAS
SAS Super FREQ

That must be a VERY old textbook! The indexing syntax v(|j,1|) instead of v[j,1] has not been used in decades.

IanWakeling
Barite | Level 11

A good point Rick. I must be showing my age as it didn't appear wrong to me! This type of syntax is from the days when not all computer keyboards had square brackets.

kindernet
Fluorite | Level 6

Thank you for the information. 

I changed the code, and it worked well. 

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