Hi,
I need to group a column based on the other common column in SAS DI.
I have below dataset as the input.
INPUT DATA:
Product date customer sales org actual
10 01/10/2015 124 IT10 110
10 01/10/2015 124 IT11 213
I want the below output,
OUTPUT:
Product date customer sales org
10 01/10/2015 124 IT10 323
Can anyone give suggestion on this?
Thanks in advance!!!
Vigneswar
Hi,
I need to group a column based on the other common column in SAS DI.
I have below dataset as the input.
INPUT DATA:
Product date customer sales org actual
10 01/10/2015 124 IT10 110
10 01/10/2015 124 IT11 213
I want the below output,
OUTPUT:
Product date customer sales org
10 01/10/2015 124 IT10 323
Can anyone give suggestion on this?
Thanks in advance!!!
Vigneswar
Assuming data is already sorted by: product date customer and sales org:
data wany;
set have;
by product date customer;
retain first_org total;
if first.customer then do;
first_org = sales_org;
total = actual;
end;
else total = sum(of total, actual);
if last.customer then do;
sales_org = first_org;
actual = total;
output;
end;
run;
A slightly different data step solution would be this:
data have;
input product date :ddmmyy10. customer sales_org $ actual;
format date ddmmyy10.;
cards;
10 01/10/2015 124 IT10 110
10 01/10/2015 124 IT11 213
;
run;
data want;
set have (rename=(sales_org=_sales_org actual=_actual));
by product date customer;
retain sales_org;
if first.customer then sales_org = _sales_org;
actual + _actual;
if last.customer then output;
drop _sales_org _actual;
run;
Note that the basic logic is the same as @Shmuel's
proc sql;
select distinct product,date,customer,min(sales_org) as sales_org, sum(actual) as actual from have group by product;
quit;
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