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# Conditional Selection of Customer data by group

Hello all,

I am doing data cleaning on a customer data. My goal is to select the 'survivor ' of the customer data based on data source, reliability and recency. To give an example I need to assign one survivor Identitynum to each Newid based on the information that Data source '0' is more reliable than '1', similarly Suspicious '0' is more reliable than '1', and the biggest ID is the most reliable than the others because it is the most recent. I need to write a code which will transform the table1 to the table2.

 ID Newid Identitynum Data Source Suspicious 1 1 13849 0 0 1392457 1 13844 1 0 1250118 9 14572 1 1 9 9 17532 1 0 37927 9 17532 1 0 1706203 10 29037 1 1 1733 10 37452 1 1 34609 10 44445 1 1

Table1

 ID newid Identitynum Data Source Suspicious Survivor 1 1 13849 0 0 1 37927 9 17532 1 0 1 1706203 10 29037 1 1 1

Table2

Thank you!

PS:Assigning the survivor based on 'suspicious' and recency when max(ID) is not equal to the latest non-suspicious(suspicious=0)  ID in the same newid group is the main problem.

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Solution
‎07-19-2018 07:47 AM
Super User
Posts: 13,950

## Re: Conditional Selection of Customer data by group

@Asli_A wrote:

Hello all,

I am doing data cleaning on a customer data. My goal is to select the 'survivor ' of the customer data based on data source, reliability and recency. To give an example I need to assign one survivor Identitynum to each Newid based on the information that Data source '0' is more reliable than '1', similarly Suspicious '0' is more reliable than '1', and the biggest ID is the most reliable than the others because it is the most recent. I need to write a code which will transform the table1 to the table2.

 ID Newid Identitynum Data Source Suspicious 1 1 13849 0 0 1392457 1 13844 1 0 1250118 9 14572 1 1 9 9 17532 1 0 37927 9 17532 1 0 1706203 10 29037 1 1 1733 10 37452 1 1 34609 10 44445 1 1

Table1

 ID newid Identitynum Data Source Suspicious Survivor 1 1 13849 0 0 1 37927 9 17532 1 0 1 1706203 10 29037 1 1 1

Table2

Thank you!

PS:Assigning the survivor based on 'suspicious' and recency when max(ID) is not equal to the latest non-suspicious(suspicious=0)  ID in the same newid group is the main problem.

If I am understanding the question is basically: get the records into a desired order and select the correct one.

This might give you a start:

```proc sort data=have;
by newid datasource suspicious descending id;
run;

data want;
set have;
by newid;
if first.newid;
run;```

All Replies
Solution
‎07-19-2018 07:47 AM
Super User
Posts: 13,950

## Re: Conditional Selection of Customer data by group

@Asli_A wrote:

Hello all,

I am doing data cleaning on a customer data. My goal is to select the 'survivor ' of the customer data based on data source, reliability and recency. To give an example I need to assign one survivor Identitynum to each Newid based on the information that Data source '0' is more reliable than '1', similarly Suspicious '0' is more reliable than '1', and the biggest ID is the most reliable than the others because it is the most recent. I need to write a code which will transform the table1 to the table2.

 ID Newid Identitynum Data Source Suspicious 1 1 13849 0 0 1392457 1 13844 1 0 1250118 9 14572 1 1 9 9 17532 1 0 37927 9 17532 1 0 1706203 10 29037 1 1 1733 10 37452 1 1 34609 10 44445 1 1

Table1

 ID newid Identitynum Data Source Suspicious Survivor 1 1 13849 0 0 1 37927 9 17532 1 0 1 1706203 10 29037 1 1 1

Table2

Thank you!

PS:Assigning the survivor based on 'suspicious' and recency when max(ID) is not equal to the latest non-suspicious(suspicious=0)  ID in the same newid group is the main problem.

If I am understanding the question is basically: get the records into a desired order and select the correct one.

This might give you a start:

```proc sort data=have;
by newid datasource suspicious descending id;
run;

data want;
set have;
by newid;
if first.newid;
run;```
New Contributor
Posts: 4

## Re: Conditional Selection of Customer data by group

Yes! This was what i needed. Thank you
☑ This topic is solved.