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ilikesas
Barite | Level 11

Hi,

 

suppose I have the following data of stock prices:

 

data price;
input a b;
datalines;
10 20
15 16
17 18
11 21
13 17
;
run;

 

what I would like to do is to transform this data into a data of changes in the prices. Right now I am doing it very inefficiently in the following way:

 

 

data price;
set price;
lag_a=lag(a);
lag_b=lag(b);
run;

data returns;
set price;
ret_a=(a-lag_a)/(lag_a);
ret_b=(b-lag_b)/(lag_b);
run;

data returns (keep=ret_a ret_b) ;
set returns;
run;

data returns ;
set returns;
a=ret_a;
b=ret_b;
run;

data returns (keep = a b);
set returns;
run;

 

Here are the 2 things which I would like to improve:

1) to make the rate of change calculation automatic --> not to type individually lag_a, lag_b .... ret_a, ret_b becasue if I have say 100 stocks it becomes tedious...

2) when I finally have the return data, I would like the variables to have their original names, for example ret_a reappears as a (please note its not simple relableing, I will need the stock return variables to have their original variable names).

 

Thank you very much!!!

1 ACCEPTED SOLUTION

Accepted Solutions
stat_sas
Ammonite | Level 13

May be this is what you are looking for

 

data want(drop=i);
set price;
array v(*) _numeric_;
do i=1 to dim(v);
v(i)=(v{i}-lag(v{i}))/lag(v{i});
end;
run;

View solution in original post

2 REPLIES 2
kannand
Lapis Lazuli | Level 10

Can you show the output you are expecting?

Kannan Deivasigamani
stat_sas
Ammonite | Level 13

May be this is what you are looking for

 

data want(drop=i);
set price;
array v(*) _numeric_;
do i=1 to dim(v);
v(i)=(v{i}-lag(v{i}))/lag(v{i});
end;
run;

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