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01-25-2017 01:04 AM

Hi,

I have a dataset of individuals already sorted on a value. I would like to assign a pairID to the first two individuals, then the next pair, and so on. If the file contains an odd number of individuals, the last three are grouped to form a triplet. I hope that makes sense and would appreciate any tips.

Thanks!

HAVE | WANT | ||

ID | ID | pairID | |

1 | 1 | 1 | |

2 | 2 | 1 | |

3 | 3 | 2 | |

4 | 4 | 2 | |

5 | 5 | 3 | |

6 | 6 | 3 | |

7 | 7 | 4 | |

8 | 8 | 4 | |

9 | 9 | 5 | |

10 | 10 | 5 | |

11 | 11 | 5 |

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Solution

01-30-2017
12:15 PM

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Posted in reply to STLT

01-25-2017 01:16 AM

Playing around with some basic math this is relatively straightforward.

Functions:

MOD()

Use NOBS option on SET statement to get the number of observations.

Use RETAIN

Data want;

set have NOBS=num end =eof;

RETAIN count;

If mod(_n_, 2) ne 0 and not eof then count+1;

run;

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Solution

01-30-2017
12:15 PM

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Posted in reply to STLT

01-25-2017 01:16 AM

Playing around with some basic math this is relatively straightforward.

Functions:

MOD()

Use NOBS option on SET statement to get the number of observations.

Use RETAIN

Data want;

set have NOBS=num end =eof;

RETAIN count;

If mod(_n_, 2) ne 0 and not eof then count+1;

run;

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Posted in reply to STLT

01-25-2017 10:42 AM

Of course I would choose to use @Reeza's solution myself, but FWIW, here is another approach outrageously not using MOD() ,

```
data want;
do _error_=1 to 2;
set sashelp.class end=last;
pairID=ifn(last and _error_=1,_n_-1,_n_);
output;
end;
run;
```

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Posted in reply to Haikuo

01-30-2017 12:18 PM

Thank you, both, for taking time to resolve this for me. I can't believe how few lines of codes are needed. I understand the logic, but am just not advanced enough to come up with it myself. Thanks again for the help!