How to filter out the number below start with "8187"? The format is string $CHAR8. Thanks
Example:
81861234
81876789
81886577
where substr(number,1,4) = '8187';
?
View solution in original post
Try
where string ^=: '8187' ;
You can see more about the =: operator at SAS Operators in Expressions
Go to the Character Comparisons link.
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