How to find a cut-off value for Estimated Probability that make an equation has the minimum value

[Terrencefung]

Hi SAS community members,

I need to find a cut-off value for Estimated Probability that make EC has the minimum value

EC= q1(x1)c1+q2(x2)c2

where q1=0.01, c1=1 , q2=0.99, c2=20

x1 is the probability of observed Type I error , x2 is the probability of observed the Type II error

q1 is the assuemd probabilty for manipulator = 0.01 (1%), and the assumend probabilty for non-manipulator is q2=0.99 (99%).

The following is the sample data 

Global Company	em	Estimated Probability
Key
1173	1	0.01095
1173	1	0.00952
1286	1	0.00804
3362	1	0.0161
3734	0	0.00812
3839	1	0.0123
3946	1	0.01109
4060	0	0.00972
4060	1	0.01077
4372	1	0.00967
4601	1	0.00978
4601	0	0.00981
4622	1	0.00922
4769	1	0.01033
5047	1	0.01023
5399	1	0.00945
6136	1	0.01154
6136	1	0.00984
6882	1	0.00917
7652	1	0.00949
7652	0	0.00958
7991	1	0.01051
8092	1	0.01075
8972	0	0.01
9538	1	0.01213
10026	1	0.00946

em=1 means the observations is a manipulator, 0 otherwise,  

Estimated Probability is the estmated probabilty calculated by a Logit model.

In my sample, there are 100 manipulators and 9,900 non-manipulators.

Could anyone please help me for this .

Many thanks for your help.

[YanXu]

I don't quite understand the statistics terms (manipulator, etc.) in your questions. I guess you can also ask this question in the statistics community while waiting for an answer here:

https://communities.sas.com/t5/SAS-Statistical-Procedures/bd-p/statistical_procedures