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emmytheduck
Calcite | Level 5

Hey all! I'm quite new to SAS. I am working with a large data set that lists members with their coverage dates. So, if I were a member and I had coverage for the entire year, there are 12 rows for me with 1/1/15, 2/1/15, and so on all the way to December.

I want to show just ONE line for each member. I need it to be the last month of coverage. For most, it will be December. I was told to use "last.incmth" (incmth is the variable). I'm not having any luck, and I don't want to make this too complicated if possible. Thank you!

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

Actually you likely want the last member ID value. A stub of code that should accomplish this is:

If the data is sorted this step isn't needed but just in case:

proc sort data=have; by memberid incmth; run;

Then to get the data you want:

Data want;

     set have;

     by memberid incmth;

     if last.membered;

run;

IF the data crosses Years and you need the last within each year you would need to add a Year value to use in the by statement: by membered year incmth;

and use last.year to get the last value for each year associated with a member.

View solution in original post

2 REPLIES 2
ballardw
Super User

Actually you likely want the last member ID value. A stub of code that should accomplish this is:

If the data is sorted this step isn't needed but just in case:

proc sort data=have; by memberid incmth; run;

Then to get the data you want:

Data want;

     set have;

     by memberid incmth;

     if last.membered;

run;

IF the data crosses Years and you need the last within each year you would need to add a Year value to use in the by statement: by membered year incmth;

and use last.year to get the last value for each year associated with a member.

emmytheduck
Calcite | Level 5

ballardw - Thank you! I actually figured it out right before you posted. I forget that I need to focus on the variable that is causing the duplicates. Thank you!

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