Hi.
I need to create a multiple array (81,81).
I've 3 columns in my data. 1st and 2nd column values ranges from 1 to 81 (these are codes for Provinces) and the 3rd column shows the distance between these provinces. The data structure is like:
A B C
1 2 200
1 3 500
. . .
1 81 300
2 1 100
2 3 250
. . .
81 80 1000;
I need to create an array/table/matrix which is 81 by 81 and shows the distance (3rd column value) between these provinces (1st and 2nd columns values).
Thanks in advance.
Hi,
Try transpose:
data have;
infile datalines;
input a b c;
datalines;
1 2 200
1 3 30
1 5 23
2 1 27
2 4 8
2 5 90
;
run;
proc sort data=have;
by a b c;
run;
proc transpose data=have out=want (drop=_name_) prefix=B;
by a;
var c;
id b;
idlabel b;
run;
The above will create Bx variables for each unique occurrence of a value in B.
Hi,
Try transpose:
data have;
infile datalines;
input a b c;
datalines;
1 2 200
1 3 30
1 5 23
2 1 27
2 4 8
2 5 90
;
run;
proc sort data=have;
by a b c;
run;
proc transpose data=have out=want (drop=_name_) prefix=B;
by a;
var c;
id b;
idlabel b;
run;
The above will create Bx variables for each unique occurrence of a value in B.
Shouldn't the distance between a=1 and b=2 be the same as a=2 and b=1?
Hi. Thanks for your reply.
Yes it is, I just mentioned randomly .
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