BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
vikram_e
Fluorite | Level 6

Hi There,

 

I am having  Macro var1 having multiple values seperated by delimitor (master list of charcter type variable), another macro var2 val seperated by dilimitor (another subgroup of Mixed type (Char+Num) ). i want to find out the common values between two macro variables. any one please help me. 

 

Macro Var1 = Name sex race occp     {all character type variables}

Macro Var2 = Name age sex salary race country {mixed type char and Num variables}

 

Solution Like  Macro Var3 = Name sex race   {only characters type vars

 

 

Thanks 

1 ACCEPTED SOLUTION

Accepted Solutions
Tom
Super User Tom
Super User

So you have these macro variables.

%let charvars = Name sex race occp ;
%let allvars = Name age sex salary race country ;

And you want to produce.

%let found=Name sex race;

It would be easier to do it with a data step (if the values of the macro variables are not longer than 32K characters).

data _null_;
  charvars="&charvars";
  allvars="&allvars";
  length found $32767 ;
  do i=1 to countw(charvars,' ');
    if indexw(upcase(allvars),upcase(scan(charvars,i,' '))) then 
      found=catx(' ',found,scan(charvars,i,' '))
    ;
  end;
  call symputx('found',found);
run;

Although you could do it inside of a macro.  You could even define the macro to work like a function since it has no need to generate SAS code.

%macro findwords(allvars,charvars);
%local i next found ;
%do i=1 %to %sysfunc(countw(&charvars,%str( )));
  %let next=%scan(&charvars,&i,%str( ));
  %if %sysfunc(indexw(%upcase(&allvars),%upcase(&next),%str( ))) %then
    %let found=&found &next 
  ;
%end;
&found.
%mend findwords;

Then you could call it to create your list.

%let found=%findwords(&allvars,&charvars);
%put &=found ;

 

View solution in original post

6 REPLIES 6
error_prone
Barite | Level 11

EDIT: this post can be ignored ... should not post without sufficient caffeine consumed.

With the names alone it is impossible to tell whether a variable is numeric or alphanumeric. You need the names of dataset and library and query sashelp.vcoulmn or another metadata-source.

 

You can select variables depending on there type from sashelp.column.

Untested code:

 

proc sql;
   select *
     from sashelp.vcolumn
       where libname = 'SASHELP' and MemName = 'CLASS' and Type = 'char'
   ;
quit;

 

Tom
Super User Tom
Super User

So you have these macro variables.

%let charvars = Name sex race occp ;
%let allvars = Name age sex salary race country ;

And you want to produce.

%let found=Name sex race;

It would be easier to do it with a data step (if the values of the macro variables are not longer than 32K characters).

data _null_;
  charvars="&charvars";
  allvars="&allvars";
  length found $32767 ;
  do i=1 to countw(charvars,' ');
    if indexw(upcase(allvars),upcase(scan(charvars,i,' '))) then 
      found=catx(' ',found,scan(charvars,i,' '))
    ;
  end;
  call symputx('found',found);
run;

Although you could do it inside of a macro.  You could even define the macro to work like a function since it has no need to generate SAS code.

%macro findwords(allvars,charvars);
%local i next found ;
%do i=1 %to %sysfunc(countw(&charvars,%str( )));
  %let next=%scan(&charvars,&i,%str( ));
  %if %sysfunc(indexw(%upcase(&allvars),%upcase(&next),%str( ))) %then
    %let found=&found &next 
  ;
%end;
&found.
%mend findwords;

Then you could call it to create your list.

%let found=%findwords(&allvars,&charvars);
%put &=found ;

 

Astounding
PROC Star

Excellent advice.  Also note, you can get rid of the local macro variable FOUND.  Remove it from the %LOCAL statement, remove the final &FOUND. line, and make this change:

 

%if %sysfunc(indexw(%upcase(&allvars),%upcase(&next),%str( ))) %then &next;

vikram_e
Fluorite | Level 6

Hi Tom

Thanks for your time to solve the issue, i appriciate your help.

 

 

ShiroAmada
Lapis Lazuli | Level 10

Try this....

 

 

%let Var1 = Name sex race occp;
%let Var2 = Name age sex salary race country;

data 
   STRING1 (keep=string1  where=(string1 is not missing) )
   STRING2 (keep=string2  where=(string2  is not missing) );

  VAR1=upcase("&var1");
  Var1wc=countw(var1);

  var2=upcase("&var2");
  var2wc=countw(var2);

do i=1 to max(var1wc,var2wc);
  length string1 string2 $32;

  string1 =scan(var1,i," ");
  string2 =scan(var2,i," ");
  output;
end;

run;


proc sql noprint;
  select coalescec(string1 ,string2 ) into: var3 separated by " ";
from WANT A , WANT B
where string1= string2 ;
quit;

 

Hope this helps.

vikram_e
Fluorite | Level 6

Hi ShiroAmanda,

 

Thank you for your time, Code was simple and easy to understand to every one. i appriciate your help.

sas-innovate-2024.png

Join us for SAS Innovate April 16-19 at the Aria in Las Vegas. Bring the team and save big with our group pricing for a limited time only.

Pre-conference courses and tutorials are filling up fast and are always a sellout. Register today to reserve your seat.

 

Register now!

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 6 replies
  • 14425 views
  • 7 likes
  • 5 in conversation