BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
SalmaTas
Fluorite | Level 6

there is a nested IF Statement i apply in excel, and i want to know how I do it in SAS Programming, i am sure it is doable, i am just not sure how to do it. 

ex: 

i have a table containing the below data

ID                     Color 

123                   Blue

123                   Yellow

123                   Green

345                   Pink

345                   Red

345                   Blue

345                   White

 

the result i want is: 

ID                     Color 

123                   Blue, Yellow, Green

123                   Blue, Yellow, Green

123                   Blue, Yellow, Green

345                   Pink, Red, Blue, White

345                   Pink, Red, Blue, White

345                   Pink, Red, Blue, White

345                   Pink, Red, Blue, White

 

 

the IF Statements i use for the first option (where there is 3 duplicated ID number, for the 9th row) is: 

=IF((A9=A8)*AND(A9=A7),G7&"," G8&","&G9,(IF((A9=A8)*AND(A9=A10),G8&"," &G9&","G10,(IF((A9=A10)*AND(A9=A11),G9&G10&G11))))

 

the IF Statements i use for the second option (where there is 4 duplicated ID number, for the 16th row) is: 

=IF((A16=A15)*AND(A16=A14)*AND(A13=A16),G13&","&G14&","&G15&","&G16,(IF((A16=A14)*AND(A16=A15)*AND(A16=A17),G14&","&G15&","&G16&","&G17,(IF((A16=A15)*AND(A16=A17)*AND(A16=A18),G15&","&G16&","&G17&","&G18,(IF((A16=A17)*AND(A16=A18)*AND(A16=A19),G16&","&G17&","&G18&","&G19)))))))

 

how do i get the same result using SAS Programming? 

1 ACCEPTED SOLUTION

Accepted Solutions
Patrick
Opal | Level 21

One way to go:

data have;
 infile datalines truncover;
 input ID Color $;
datalines; 
123 Blue
123 Yellow
123 Green
345 Pink
345 Red
345 Blue
345 White
;
run;

proc transpose data=have out=inter prefix=_color;
  by id;
  var color;
run;

data want(drop=_:);
  merge have(keep=id) inter;
  by id;
  length color $255;
  color=catx(',',of _color:);
run;

 

or this way:


data want(drop=_:);
  set have(keep=id);
  by id;
  length color $255;
  retain color;
  if first.id then
    do;
      call missing(color);
      do until(last._id2);
        set have(rename=(id=_id2 color=_color2));
        by _id2;
        color=catx(',',color,_color2);
      end;
    end;
run;

 

or this way:


data inter(drop=_:);
  set have(rename=(color=_color));
  by id;
  length color $255;
  retain color;
  color=catx(',',color,_color);
  if last.id then
    do;
      output;
      call missing(color);
    end;
run;

proc sql;
  create table want as
    select r.id, r.color
    from have l, inter r
    where l.id=r.id
  ;
quit;

 

View solution in original post

5 REPLIES 5
kannand
Lapis Lazuli | Level 10

The actual Excel sheet may help. Is it possible to attach here ?

Kannan Deivasigamani
SalmaTas
Fluorite | Level 6

yes, please find the atatched excel sheet 

Patrick
Opal | Level 21

One way to go:

data have;
 infile datalines truncover;
 input ID Color $;
datalines; 
123 Blue
123 Yellow
123 Green
345 Pink
345 Red
345 Blue
345 White
;
run;

proc transpose data=have out=inter prefix=_color;
  by id;
  var color;
run;

data want(drop=_:);
  merge have(keep=id) inter;
  by id;
  length color $255;
  color=catx(',',of _color:);
run;

 

or this way:


data want(drop=_:);
  set have(keep=id);
  by id;
  length color $255;
  retain color;
  if first.id then
    do;
      call missing(color);
      do until(last._id2);
        set have(rename=(id=_id2 color=_color2));
        by _id2;
        color=catx(',',color,_color2);
      end;
    end;
run;

 

or this way:


data inter(drop=_:);
  set have(rename=(color=_color));
  by id;
  length color $255;
  retain color;
  color=catx(',',color,_color);
  if last.id then
    do;
      output;
      call missing(color);
    end;
run;

proc sql;
  create table want as
    select r.id, r.color
    from have l, inter r
    where l.id=r.id
  ;
quit;

 

SalmaTas
Fluorite | Level 6
thanks a lot for the great support.
Kurt_Bremser
Super User

Still another method:

 

data want (drop=oldcolor count index);
set have (rename=(color=oldcolor));
by id;
length color $ 200;
if first.id
then do;
  count = 0;
  color = '';
end;
color = catx(',',trim(color),oldcolor);
count + 1;
if last.id
then do;
  do index = 1 to count;
    output;
  end;
end;
run;
  

sas-innovate-2024.png

Don't miss out on SAS Innovate - Register now for the FREE Livestream!

Can't make it to Vegas? No problem! Watch our general sessions LIVE or on-demand starting April 17th. Hear from SAS execs, best-selling author Adam Grant, Hot Ones host Sean Evans, top tech journalist Kara Swisher, AI expert Cassie Kozyrkov, and the mind-blowing dance crew iLuminate! Plus, get access to over 20 breakout sessions.

 

Register now!

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 5 replies
  • 1266 views
  • 2 likes
  • 4 in conversation