data test;
x = 'charles dickens' ;
y =scan (x ,2 ) ;
run;
length of scan function is said to be 200 , then why i am getting the length of y as 15 . substr function takes the length of input function is scan function also working like this ? please help .
Please read the SAS 9.4 documentation at http://documentation.sas.com/?docsetId=lefunctionsref&docsetTarget=p0jshdjy2z9zdzn1h7k90u99lyq6.htm&...
which says
In a DATA step, if the SCAN function returns a value to a variable that has not yet been given a length, that variable is given the length of the first argument. This behavior is different from the behavior in previous releases of SAS. In previous releases, code that created a variable with a length of 200 might have produced a variable with a length that was greater than expected. If you need the SCAN function to assign a variable with a value that is different from the length of the first argument, use a LENGTH statement.
because Y takes the lenght of X since Y was not declared until you assigned Y to scan X
data test;
lenght y $200;
x = 'charles dickens' ;
y =scan (x ,2 ) ;
run;
Don't miss out on SAS Innovate - Register now for the FREE Livestream!
Can't make it to Vegas? No problem! Watch our general sessions LIVE or on-demand starting April 17th. Hear from SAS execs, best-selling author Adam Grant, Hot Ones host Sean Evans, top tech journalist Kara Swisher, AI expert Cassie Kozyrkov, and the mind-blowing dance crew iLuminate! Plus, get access to over 20 breakout sessions.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.