I have data set dtset1.
sn. stdt;
1 10/10/2010
2 10/19/2011
stdt is a character variable with length 10.
I need to convert this into numeric date like datetime20.
I tried this;
data new-dtset;
set dtset1 (rename=(stdt=stdt_n));
stdt=input(stdt_n, date9.);
format stdt datetime20.;
drop stdt_n;
run;
but It didn't work, It's converting to numberic but showing as missing value.
I need help to solve this problem.
Thank you
Replace
stdt=input(stdt_n, date9.);
with
stdt = input(stdt_n,mmddyy10.) * 86400;
Since you want it to display as a datetime value, it needs to count the seconds from 01jan1960 instead of just the days.
First you need to change the informat reading the date and secondly you must convert that date value into a datetime value using the dhms function.
data newdtset;
set dtset1 (rename=(stdt=stdt_n));
stdt=dhms(input(stdt_n, mmddyy10.),0,0,0);
format stdt datetime20.;
drop stdt_n;
run;
Regards,
Michael
Thank you Michael
Replace
stdt=input(stdt_n, date9.);
with
stdt = input(stdt_n,mmddyy10.) * 86400;
Since you want it to display as a datetime value, it needs to count the seconds from 01jan1960 instead of just the days.
Directly use informat .
option datestyle=mdy; data have; input sn stdt : $20.; d=input(stdt,anydtdtm20.); format d datetime.; cards; 1 10/10/2010 2 10/19/2011 ; run;
Xia Keshan
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