Hi
I need to delete records from table temp_weekly_data where the date is less than today and status is equal to A
following code is deleting records where the date is less than today(), ignoring if the staus value
data temp_weekly_data;
set DB.TABLE(where = (&date1 <= date_my < &date2 ) );
if status in ("A") and datepart(date_my) < today() then delete;
run;
staus field is of type Text, 10 character length
Thanks in advance
Your code should work fine only in case status is always in capital letter.
Are &date1 and &date2 given as datetime or date only ?
Are your where consistent with the IF statement ? (either date variable or datetime variable)
You may test:
data temp_weekly_data;
set DB.TABLE(where = (&date1 <= date_my < &date2 ) );
if upcase(status) = "A"
and datepart(date_my) < today() then delete;
run;
You mentioned that status is a 10 character length field. Are you possibly wanting to delete a record if its status field contains an "A"? If so, you could use:
data db.table; informat status $10.; length status $10; input status; cards; A BC A ABC BCD ; data temp_weekly_data; set DB.TABLE (where = (&date1 <= date_my < &date2 ) ); if find(status,"A") and datepart(date_my) < today() then delete; run;
Art, CEO, AnalystFinder.com
Don't miss out on SAS Innovate - Register now for the FREE Livestream!
Can't make it to Vegas? No problem! Watch our general sessions LIVE or on-demand starting April 17th. Hear from SAS execs, best-selling author Adam Grant, Hot Ones host Sean Evans, top tech journalist Kara Swisher, AI expert Cassie Kozyrkov, and the mind-blowing dance crew iLuminate! Plus, get access to over 20 breakout sessions.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.