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date manupulation

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Super Contributor
Posts: 303
Accepted Solution

date manupulation

[ Edited ]

Hello-,

 

I have a date format below. I want to drop the last four digit ie 1950 and 1421 from the date and subtract 2/10/2017-2/9/2017

  data AA;

input  ADT_IN  ADT_OUT;

   
2/9/2017 1950 2/10/2017 1421
2/8/2017 1750 2/10/2017 1240
2/7/2017 1143 2/9/2017 1250
2/8/2017 1256 2/11/2017 0042
   
   
   
   
   
2/8/2017 1357 2/9/2017 1339
2/8/2017 1236 2/10/2017 1809
   
2/8/2017 1236 2/10/2017 1809

;

 

 

 

How do I perform length of stay (LOS) using the above data.  LOS= out-in above


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Solution
‎07-28-2017 01:57 AM
Super Contributor
Posts: 303

Re: date manupulation

Posted in reply to subobscure

works

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.)/365;
run;

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All Replies
Super User
Posts: 19,805

Re: date manupulation

Posted in reply to desireatem

SCAN to separate components

INPUT to convert character to date

 

Super Contributor
Posts: 303

Re: date manupulation

I do not understand.

Occasional Contributor
Posts: 11

Re: date manupulation

Posted in reply to desireatem
  1. scan the date using spaces as delimiter
  2. Convert the date to numeric
  3. Subtract one value from the other

data a;
date1="2/9/2017 1950";
date2="2/10/2017 1421";

diff=input(scan(date2,1," "),ddmmyy10.)-input(scan(date1,1," "),ddmmyy10.);
run;sas.JPG

 

Super Contributor
Posts: 303

Re: date manupulation

[ Edited ]
Posted in reply to subobscure

I did not work.

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.);
run;

Super User
Posts: 7,782

Re: date manupulation

Posted in reply to desireatem

Post your example dataset (in a data step!), so we can see the content and attributes of your variables.

"It did not work" is about as helpful as "a bicycle tipped over in Beijing". So post the log of your code, and how the result (if there was one) differed from your expectations.


desireatem wrote:

I did not work.

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.);
run;


 

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Super Contributor
Posts: 303

Re: date manupulation

Posted in reply to KurtBremser

Thank you

Solution
‎07-28-2017 01:57 AM
Super Contributor
Posts: 303

Re: date manupulation

Posted in reply to subobscure

works

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.)/365;
run;

Occasional Contributor
Posts: 11

Re: date manupulation

Posted in reply to desireatem
Good that I could be of help.
I concur with what @KurtBremser said. If a piece of code is not working for you, you are supposed to give the snapshot of your log
☑ This topic is solved.

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