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date manupulation

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Super Contributor
Posts: 297
Accepted Solution

date manupulation

[ Edited ]

Hello-,

 

I have a date format below. I want to drop the last four digit ie 1950 and 1421 from the date and subtract 2/10/2017-2/9/2017

  data AA;

input  ADT_IN  ADT_OUT;

   
2/9/2017 1950 2/10/2017 1421
2/8/2017 1750 2/10/2017 1240
2/7/2017 1143 2/9/2017 1250
2/8/2017 1256 2/11/2017 0042
   
   
   
   
   
2/8/2017 1357 2/9/2017 1339
2/8/2017 1236 2/10/2017 1809
   
2/8/2017 1236 2/10/2017 1809

;

 

 

 

How do I perform length of stay (LOS) using the above data.  LOS= out-in above


Accepted Solutions
Solution
4 weeks ago
Super Contributor
Posts: 297

Re: date manupulation

works

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.)/365;
run;

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All Replies
Super User
Posts: 17,864

Re: date manupulation

SCAN to separate components

INPUT to convert character to date

 

Super Contributor
Posts: 297

Re: date manupulation

I do not understand.

Occasional Contributor
Posts: 10

Re: date manupulation

  1. scan the date using spaces as delimiter
  2. Convert the date to numeric
  3. Subtract one value from the other

data a;
date1="2/9/2017 1950";
date2="2/10/2017 1421";

diff=input(scan(date2,1," "),ddmmyy10.)-input(scan(date1,1," "),ddmmyy10.);
run;sas.JPG

 

Super Contributor
Posts: 297

Re: date manupulation

[ Edited ]

I did not work.

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.);
run;

Super User
Posts: 6,946

Re: date manupulation

Post your example dataset (in a data step!), so we can see the content and attributes of your variables.

"It did not work" is about as helpful as "a bicycle tipped over in Beijing". So post the log of your code, and how the result (if there was one) differed from your expectations.


desireatem wrote:

I did not work.

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.);
run;


 

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Super Contributor
Posts: 297

Re: date manupulation

Thank you

Solution
4 weeks ago
Super Contributor
Posts: 297

Re: date manupulation

works

 

data D_HPT;
set D_HPT;
los=input(scan(ADT_out,1," "),ddmmyy10.)-input(scan(ADT_IN,1," "),ddmmyy10.)/365;
run;

Occasional Contributor
Posts: 10

Re: date manupulation

Good that I could be of help.
I concur with what @KurtBremser said. If a piece of code is not working for you, you are supposed to give the snapshot of your log
☑ This topic is SOLVED.

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