## creating new rows for long periods

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Frequent Contributor
Posts: 133

# creating new rows for long periods

``````id rx start_date   days_supply
1 a    1/1/2005     90
2  b   2/2/2004      60

``````

Hi all, I have the above dataset, I want to divide the periods that the patient can take drug were days supply represent the days the patients taked the drug. For simplicity, if the patient have 90 days means patient takes the drug for 3 months. 60 for two months and so on. Here is the output I am looking for

``````id rx start_date   days_supply
1  a   1/1/2005     30
1  a   2/1/2005     30
1  a   3/1/2005    30
2  b   2/2/2004   30
2  b   3/2/2004   30 ``````

Accepted Solutions
Solution
‎10-27-2016 08:17 AM
Super User
Posts: 10,395

## Re: creating new rows for long periods

``````data have;
infile datalines;
input id rx \$ start_date mmddyy10. days_supply;
format start_date mmddyy10.;
datalines;
1 a 01/01/2005 90
2 b 02/02/2004 60
; run;

data want;
set have;
months = int(days_supply/30);
supply=30;
do i=1 to months;
date = intnx('month',start_date,i-1,'s');
output;
end;
KEEP ID RX supply date;
format date mmddyy10.;
run;``````

All Replies
Posts: 1,699

## Re: creating new rows for long periods

data have;

infile datalines;

input id rx start_date mmddyy10. days_supply;

format start_date mmddyy10.;

datalines;

1 a 01/01/2005 90

2 b 02/02/2004 60

; run;

data want;

set have;

months = days_supply / 30;   /* or ceil(days_supply/30)  */

start_date_in = start_date;

do i=1 to months;

start_date = intnx('MONth', start_date_in, i-1) + day(start_date_in) -1;

days_supply = 30;

output;

end;

run;

Solution
‎10-27-2016 08:17 AM
Super User
Posts: 10,395

## Re: creating new rows for long periods

``````data have;
infile datalines;
input id rx \$ start_date mmddyy10. days_supply;
format start_date mmddyy10.;
datalines;
1 a 01/01/2005 90
2 b 02/02/2004 60
; run;

data want;
set have;
months = int(days_supply/30);
supply=30;
do i=1 to months;
date = intnx('month',start_date,i-1,'s');
output;
end;
KEEP ID RX supply date;
format date mmddyy10.;
run;``````
Frequent Contributor
Posts: 133

## Re: creating new rows for long periods

Thank you!

☑ This topic is solved.

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