Hi,
I got a datasæt with many rows and a char variable with content of a list of numbers separated by :
41:31: 53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62
I need to count and sum the number of specific numbers to create a classification as this:
Group1 when number is in(48,47,46,45,44,43,42,41,31,32,33,34,35,36) and I need to sum the found number of string
Group2 when number is in(55,54,53,52,51,61,62,63,64,) and I need to sum the found number of string
So the result is Group1=11 and Group2=7
Any ideas how to do it ?
Thanks in advance.
Show some example input and the desired output for that input.
It is not at all clear what you are summing.
When I look at your group 2 example
41:31:53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62 value occurrences 55 0 54 1 53 2 52 2 51 1 61 2 62 1 63 0 64 0
I get a total of 9 occurrences of the values or 6 values found. So how do you get 7?
This gets the counts of the substrings in group2 as an example:
data example; infile datalines truncover; informat string $100.; input string; array g {9} $ _temporary_ ("55" "54" "53" "52" "51" "61" "62" "63" "64") ; array gcount {9}; do i= 1 to dim(g); gcount[i] =count(string,g[i],'it'); end; drop i; datalines; 41:31:53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62 ; run;
Gcount1 will have the count of the 55 in the string variable. Gcount9 will have the count of the 64s.
The sum of the counts could be:
grp2sum= sum(of gcount(*));
You would need a separate temporary array and separate counting array (unless you are VERY careful) to use this approach for both groups.
something like this then u can extend your idea for another one
data test;
length z $8.;
a= '41:31:53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62';
b ='48,47,46,45,44,43,42,41,31,32,33,34,35,36';
sum = 0;
do until(z='');
count+1;
z = scan(a, count,":");
if find(b,trim(z)) then sum+z;
else sum+0;
end;
drop i count z;
run;
Show some example input and the desired output for that input.
It is not at all clear what you are summing.
When I look at your group 2 example
41:31:53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62 value occurrences 55 0 54 1 53 2 52 2 51 1 61 2 62 1 63 0 64 0
I get a total of 9 occurrences of the values or 6 values found. So how do you get 7?
This gets the counts of the substrings in group2 as an example:
data example; infile datalines truncover; informat string $100.; input string; array g {9} $ _temporary_ ("55" "54" "53" "52" "51" "61" "62" "63" "64") ; array gcount {9}; do i= 1 to dim(g); gcount[i] =count(string,g[i],'it'); end; drop i; datalines; 41:31:53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62 ; run;
Gcount1 will have the count of the 55 in the string variable. Gcount9 will have the count of the 64s.
The sum of the counts could be:
grp2sum= sum(of gcount(*));
You would need a separate temporary array and separate counting array (unless you are VERY careful) to use this approach for both groups.
This is the solution that works for me on my own data - and in additon very nice and elegant solution. Thank you very much.
Hi,
In addition also look at PRXCHANGE with COUNT .
DATA test;
string="41:31:53:52:32:33:34:35:36:54:53:52:51:61:48:47:46:45:61:62";
group1="48,47,46,45,44,43,42,41,31,32,33,34,35,36";
group2="55,54,53,52,51,61,62,63,64";
Count_Group1=COUNT(prxchange("s/(48|47|46|45|44|43|42|41|31|32|33|34|35|36)/G1/i",-1,string),"G1");
Count_Group2=COUNT(prxchange("s/(55|54|53|52|51|61|62|63|64)/G2/i",-1,string),"G2");
run;
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