I am looking for some help on creating a macro that will identify continuous enrollment with a given gap. For example, we will allow a month gap and still allow continuous enrollment. The data structure I have is....
Memb_id enroll_yrmo (number - not date)
1 201701
1 201702
1 201703
1 201704
1 201705
...
1 201712
I have done this before but it was with from and thru dates with a single record per member. Now, I have a record for every month and it isn't even a date. It is a number. I would love your help and input.
Here's one approach, assuming your data set is already sorted:
data want;
set have;
by memb_id;
dif_date = dif(enroll_yrmo);
month = mod(enroll_yrmo, 100);
if first.memb_id then do;
group=1;
return;
end;
if month > 1 and dif_date=1 then return;
if month=1 and dif_date=89 then return;
group + 1;
run;
Since you described the result, but didn't illustrate it, here's what this is doing. It assumes that a "gap" means that a year/month is missing from the sequence (for the same value of MEMB_ID). It creates a new variable (GROUP) that is 1 for the first set of sequential observations, but increases whenever a gap is found.
Don't miss out on SAS Innovate - Register now for the FREE Livestream!
Can't make it to Vegas? No problem! Watch our general sessions LIVE or on-demand starting April 17th. Hear from SAS execs, best-selling author Adam Grant, Hot Ones host Sean Evans, top tech journalist Kara Swisher, AI expert Cassie Kozyrkov, and the mind-blowing dance crew iLuminate! Plus, get access to over 20 breakout sessions.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.