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mattteale
Fluorite | Level 6

Hi,

 

By way of example, I have two groups of strings as shown below, a1-a3 and b1-b3.

 

I want to know if at least one of the strings in a1-a3 is equal to at least one of the strings in b1-b3. Then flag the rows which satisfy this.

 

I imagine this will be done using arrays and a do loop. I realise my attempt in the code below will only work if all a1-a3 are identical to b1-b3.

 

I would really appreciate some help here.

 

Thanks a lot

 

Matt

 

data table ;
input a1 $ a2 $ a3 $ b1 $ b2 $ b3 $ match $ ;
cards ;
a b c a b c Yes
a b c a d e Yes 
a b c d e f no 
a b c a b e Yes
; 
run ;

data table ;
set table ;
array check1 a1-a3 ;
array check2 b1-b3 ;
do i=1 to 3 ;
if check1(i)=check2(i) then match =1 ;
else match=0 ;
end ;
run ;

 

 

1 ACCEPTED SOLUTION

Accepted Solutions
RW9
Diamond | Level 26 RW9
Diamond | Level 26

Something like:

data table ;
  input a1 $ a2 $ a3 $ b1 $ b2 $ b3 $;
cards ;
a b c a b c
a b c a d e
a b c d e f 
a b c a b e
; 
run;

data want;
  set table;
  array a{3};
  do i=1 to dim(a);
    if whichc(a{i},of b:) then match="yes";
  end;
run;

 

 

 

View solution in original post

3 REPLIES 3
Kurt_Bremser
Super User

Just a little change in the logic:

data table;
set table;
array check1 a1-a3;
array check2 b1-b3;
match = 0;
do i = 1 to 3;
  if check1{i} = check2{i} then match = 1;
end;
run;
mattteale
Fluorite | Level 6

Thank you so much pal

RW9
Diamond | Level 26 RW9
Diamond | Level 26

Something like:

data table ;
  input a1 $ a2 $ a3 $ b1 $ b2 $ b3 $;
cards ;
a b c a b c
a b c a d e
a b c d e f 
a b c a b e
; 
run;

data want;
  set table;
  array a{3};
  do i=1 to dim(a);
    if whichc(a{i},of b:) then match="yes";
  end;
run;

 

 

 

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