I want to remove leading zero and trailing zero, so I want to modify my variable by doing below:
var2 = strip(var1,'0');
I got the error message:
The STRIP function call has too many arguments.
anybody helps to solve this?
thanks
Unfortunately STRIP() does not have that function. For details, please refer strip function
For your problems, you can either try using a combination of multiple functions/multiple steps, Or using PRX function in one shot:
DATA HAVE;
INPUT STR $20.;
CARDS;
0012200
00023
22000
200340
;
DATA WANT;
SET HAVE;
NEW_STR=PRXCHANGE('s/^ *0*|0* *$//io', -1, str);
run;
Unfortunately STRIP() does not have that function. For details, please refer strip function
For your problems, you can either try using a combination of multiple functions/multiple steps, Or using PRX function in one shot:
DATA HAVE;
INPUT STR $20.;
CARDS;
0012200
00023
22000
200340
;
DATA WANT;
SET HAVE;
NEW_STR=PRXCHANGE('s/^ *0*|0* *$//io', -1, str);
run;
Don't miss out on SAS Innovate - Register now for the FREE Livestream!
Can't make it to Vegas? No problem! Watch our general sessions LIVE or on-demand starting April 17th. Hear from SAS execs, best-selling author Adam Grant, Hot Ones host Sean Evans, top tech journalist Kara Swisher, AI expert Cassie Kozyrkov, and the mind-blowing dance crew iLuminate! Plus, get access to over 20 breakout sessions.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.