turn on suggestions

Auto-suggest helps you quickly narrow down your search results by suggesting possible matches as you type.

Showing results for

Find a Community

- Home
- /
- SAS Programming
- /
- Base SAS Programming
- /
- Standardizing observations

Topic Options

- RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page

- Mark as New
- Bookmark
- Subscribe
- RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

05-25-2017 01:38 AM - edited 05-25-2017 01:39 AM

I want to standardize the variable titled "Value" such that it has a maximum value of X (e.g., -2) and a minimum value of Y (e.g., 10). To do so, I want that all observations are adjusted in the same way.

Please see below the code I have written so far and it is based on a post by @Rick_SAS (please see link below):

```
DATA work.sample;
INPUT Institution $ Value;
DATALINES;
ABC 0.8
BCD 0.9
CDF 1.2
DEF -0.1
;
RUN;
```

```
*Normalize the data above to a max of 1 and min of 0 such that all other observations (non-max and non-min values) will also change;
proc stdize data=work.sample out=work.sample2 method=RANGE;
var Value;
run;
```

`/*To change to a different range (e.g., [-1,1])*/`

data work.sample3;
set work.sample2;
Value = 2*Value - 1;
run;

**Question 1: **

By adjusting the range, all of the non-boundary values will also be adjusted, right? For instance, if we have 3 observations (e.g., -10, 5, 10), then the median will also change such that it incorporates the adjustment of the upper and lower boundary (which changes to 0 and 1, respectively).**Question 2:**

If I want to have an upper bound of 10 and a lower bound of 2 what change do I have to make in the last part of the code?

**Link: **https://communities.sas.com/t5/SAS-Procedures/scaling-variable-in-a-dataset/td-p/13294

Accepted Solutions

Solution

05-25-2017
11:24 AM

- Mark as New
- Bookmark
- Subscribe
- RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Posted in reply to Yegen

05-25-2017 10:06 AM

Q1: Correct.

Q2: You can use the MULT= and ADD= options to scale and translate directly in PROC STDIZE. So insted of STDIZE followed by a DATA step, you can get sample3 by using

```
proc stdize data=work.sample out=work.sample4 method=RANGE mult=2 add=-1;
var Value;
run;
```

In particular, if you want an upper bound of 10 and a lower bound of 2, then the scale of the data is (10-2)=8 and the offset is 2, so you can use

```
proc stdize data=work.sample out=work.sample5 method=RANGE mult=8 add=2;
var Value;
run;
```

All Replies

Solution

05-25-2017
11:24 AM

- Mark as New
- Bookmark
- Subscribe
- RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Posted in reply to Yegen

05-25-2017 10:06 AM

Q1: Correct.

Q2: You can use the MULT= and ADD= options to scale and translate directly in PROC STDIZE. So insted of STDIZE followed by a DATA step, you can get sample3 by using

```
proc stdize data=work.sample out=work.sample4 method=RANGE mult=2 add=-1;
var Value;
run;
```

In particular, if you want an upper bound of 10 and a lower bound of 2, then the scale of the data is (10-2)=8 and the offset is 2, so you can use

```
proc stdize data=work.sample out=work.sample5 method=RANGE mult=8 add=2;
var Value;
run;
```

- Mark as New
- Bookmark
- Subscribe
- RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Posted in reply to Rick_SAS

05-25-2017 11:24 AM

Perfect, thank you for this helpful reply. Lastly, I am wondering if there is any way to use "proc stdize" such that one can directly specify the upper and lower bound without having to add / subtract or multiply / divide values. For instance, if one wants to have a lower bound of 1.61 and an upper bound of 3.14, would it be possibly to directly specify these bounds?

- Mark as New
- Bookmark
- Subscribe
- RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Posted in reply to Yegen

05-25-2017 11:29 AM

```
%let lower = 1.61;
%let upper = 3.14;
%let range = %sysevalf(&upper - &lower);
proc stdize data=sample out=sample6 method=RANGE mult=&range add=&lower;
var Value;
run;
```

- Mark as New
- Bookmark
- Subscribe
- RSS Feed
- Permalink
- Email to a Friend
- Report Inappropriate Content

Posted in reply to Rick_SAS

05-25-2017 11:37 AM

This is exactly what I needed! Thank you very much, @Rick_SAS!