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Posts: 24

# Rounding down by 2 dp

Hi,

What function can be used to round down a number by 2 dp, for instance if I have the value of 0.99856 how can I round this down to 0.99?

Many Thanks

Accepted Solutions
Solution
‎01-29-2018 12:04 PM
Super User
Posts: 22,850

## Re: Rounding down by 2 dp

That's not rounding, that's truncation, rounding to 2 decimal places would be 1.00.

Note, please use full words, ie dp=decimal place is my assumption. Not everyone here will know your terminology.

``````data want;

x=0.99856;

y=floor(x*100)/100;
y=round(y, 0.01);

put x= y=;

run;``````

Hi,

What function can be used to round down a number by 2 dp, for instance if I have the value of 0.99856 how can I round this down to 0.99?

Many Thanks

All Replies
Solution
‎01-29-2018 12:04 PM
Super User
Posts: 22,850

## Re: Rounding down by 2 dp

That's not rounding, that's truncation, rounding to 2 decimal places would be 1.00.

Note, please use full words, ie dp=decimal place is my assumption. Not everyone here will know your terminology.

``````data want;

x=0.99856;

y=floor(x*100)/100;
y=round(y, 0.01);

put x= y=;

run;``````

Hi,

What function can be used to round down a number by 2 dp, for instance if I have the value of 0.99856 how can I round this down to 0.99?

Many Thanks

User
Posts: 1

## Re: Rounding down by 2 dp

HI Reeza,

Thanks for this solution! Just a question about "y=round(y, 0.01)" as I'm not sure if it's necessary. When I run your code without it, it seems to work fine. Am I missing something? Thanks!

-Joey
Super User
Posts: 22,850

## Re: Rounding down by 2 dp

It depends on what you want. Round will round the variable to the nearest second decimal place in this case. I think this is the same as using 8.2 format to display your data. However, 8.2 only controls the display, the value in the table would still be the actual value, so it depends on what you're trying to do overall.

Super User
Posts: 6,541

## Re: Rounding down by 2 dp

Can you have negative numbers, such as:

-0.98776

If so, what result would you want to see?

x = int(100*x) / 100;

☑ This topic is solved.