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Question on arithmetic conversion

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New Contributor
Posts: 2

Question on arithmetic conversion

Hello,

 

I am pretty new to SAS but I hve to maintain some older programs. Now I am stuck with a problem.

 

I have a program that does this:

PROC MEANS NOPRINT;
VAR AMOUNT AVG1 AVG2;
BY OBJNAME;
OUTPUT OUT=WORK.SUMM1
SUM(AMOUNT) = AMOUNT
MEAN(AVG1 AVG2) =
AVG1 AVG2 ;

 

Sadly the input data of AVG1 and AVG2 is not an average at all but the cumulated data, so to get real averages at the end I would have to do sum up AVG1 and AVG2 for each OBJNAME and divide it by AMOUNT. 

 

If I do 

PROC MEANS NOPRINT;
VAR AMOUNT AVG1 AVG2;
BY OBJNAME;
OUTPUT OUT=WORK.SUMM1
SUM(AMOUNT) = AMOUNT
SUM(AVG1 AVG2) =
AVG1 AVG2 ;

it looks nice but I still need the division, my idea was putting in something like 

AVG1= AVG1/AMOUNT

but I didn't find a way how this could work. 

 

Maybe someone van give me a hint how to do this?

Super User
Posts: 7,809

Re: Question on arithmetic conversion

Posted in reply to wetzer123
data summ1;
set dataset (rename=(
  amount=oldamount
  avg1=oldavg1
  avg2=oldavg2
));
by objname;
if first.objname
then do;
  amount = 0;
  avg1 = 0;
  avg2 = 0;
end;
amount + oldamount;
avg1 + oldavg1;
avg2 + oldavg2;
if last.objname
then do;
  avg1 = avg1 / amount;
  avg2 = avg2 / amount;
  output;
end;
drop oldamount oldavg1 oldavg2;
run;

"Manual" solution.

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Maxims of Maximally Efficient SAS Programmers
New Contributor
Posts: 2

Re: Question on arithmetic conversion

Posted in reply to KurtBremser

I will have to check this, as I am not shure wether it will no confuse with my data step.

 

Super User
Posts: 7,809

Re: Question on arithmetic conversion

Posted in reply to wetzer123

Unless you make use of the auomatically created _type_ and _freq_ variables, you should get the right output.

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Maxims of Maximally Efficient SAS Programmers
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