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cho16
Obsidian | Level 7

Hi ,

 

I have a dataset that needs to identify the office hours that has opened after 5 PM.

If any of the office hour days that has opened after 5pm needs to create an Indicator Y ; if not indicator has to display as N. 

 

data test;

input Monday $1-15 Tuesday $16-31 wednesday $32-47 Thursday $48-64 Friday $65-79 Saturday $80-96 Sunday $97-111;

datalines;

08:00AM-05:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-03:00PM 08:00AM-03:00PM 08:00AM-06:00PM 08:00AM-02:00PM

08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM

08:30AM-02:30PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-06:00PM

10:00AM-02:30PM 08:00AM-02:00PM 08:00AM-06:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM

09:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM

04:00AM-09:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-06:00PM

;

run;

 

My code:

data after_5pmHours;

set test;

Monday1 = input(substr(Monday,9,2), 8.);

if Monday1 = 12 and substr(Monday,14,2) = 'PM' then Indicator = 'N';

else if Monday1 > 5 and substr(Monday,14,2) = 'PM' then Indicator = 'Y';

else Indicator = 'N';

run;

 

Thanks for your help

 

 

 

1 ACCEPTED SOLUTION

Accepted Solutions
LaurieF
Barite | Level 11

I've simplified the data lines coding, and put it all in one step. Turning the data into SAS time values makes things much easier.

 

data after_5pm;
array days[7] $ 15 monday tuesday wednesday thursday friday saturday sunday;
input (monday tuesday wednesday thursday friday saturday sunday) ($15. +1);
indicator = 'N';
do i = 1 to 7 until(indicator = 'Y');
   if input(scan(days[i], 2, '-'), time.) > '17:00:00't then
      indicator = 'Y';
   end;
keep monday tuesday wednesday thursday friday saturday sunday indicator;
datalines;
08:00AM-05:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-03:00PM 08:00AM-03:00PM 08:00AM-06:00PM 08:00AM-02:00PM
08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM
08:30AM-02:30PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-06:00PM
10:00AM-02:30PM 08:00AM-02:00PM 08:00AM-06:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM
09:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM
04:00AM-09:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-06:00PM
;
run;

View solution in original post

2 REPLIES 2
LaurieF
Barite | Level 11

I've simplified the data lines coding, and put it all in one step. Turning the data into SAS time values makes things much easier.

 

data after_5pm;
array days[7] $ 15 monday tuesday wednesday thursday friday saturday sunday;
input (monday tuesday wednesday thursday friday saturday sunday) ($15. +1);
indicator = 'N';
do i = 1 to 7 until(indicator = 'Y');
   if input(scan(days[i], 2, '-'), time.) > '17:00:00't then
      indicator = 'Y';
   end;
keep monday tuesday wednesday thursday friday saturday sunday indicator;
datalines;
08:00AM-05:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-03:00PM 08:00AM-03:00PM 08:00AM-06:00PM 08:00AM-02:00PM
08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM
08:30AM-02:30PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-06:00PM
10:00AM-02:30PM 08:00AM-02:00PM 08:00AM-06:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM
09:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM 08:00AM-02:00PM
04:00AM-09:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-05:00PM 08:00AM-06:00PM
;
run;
cho16
Obsidian | Level 7

Thanks Laurie.. The code works perfectly.

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