proc sql;
create table want as
select *
from have
group by loc,car
having date=min(date) and time=min(time);
quit;
There is a glitch in @novinosrin SQL and it wouldn't return the desired result.
If you want us to post tested code then please make the effort and post sample data in the form of a working and tested SAS data step as I've done below.
Don't expect us to do such prep work for you or else get less answers, slower and less responses and untested code.
data have;
infile datalines truncover dlm=' ';
input LOC $ CAR DATE:ddmmyy. TIME :time.;
format date date9. time time.;
datalines;
A 123 01/04/10 13:35
A 123 01/05/10 02:35
A 123 01/05/10 13:45
B 123 01/05/12 04:45
B 123 01/05/15 00:35
B 124 01/05/10 15:55
C 123 01/05/17 12:00
C 124 01/05/11 05:30
C 124 01/05/12 18:00
;
run;
proc sql;
create table want as
select *
from have
group by loc,car
having (date*86400+time)=min((date*86400+time))
;
quit;
data have;
infile datalines truncover dlm=' ';
input LOC $ CAR DATE:ddmmyy. TIME :time.;
format date date9. time time.;
datalines;
A 123 01/04/10 13:35
A 123 01/05/10 02:35
A 123 01/05/10 13:45
B 123 01/05/12 04:45
B 123 01/05/15 00:35
B 124 01/05/10 15:55
C 123 01/05/17 12:00
C 124 01/05/11 05:30
C 124 01/05/12 18:00
;
run;
proc sort data=have;
by _all_;
run;
data want;
set have;
by loc car;
if first.car;
run;
This minimum by group is done very simply in PROC SUMMARY if you use actual SAS datetime values (which you should be using anyway). No sorting needed. No writing your own code in a datastep needed.
proc summary data = have nway;
class loc car;
var datetime;
output out=want min=min_datetime;
run;
Similar to @Patrick's code, maybe a bit less cryptic :
proc sql;
create table want as
select
loc,
car,
dhms(date,hour(time),minute(time),0) as datetime format=datetime16.
from have
group by loc, car
having datetime = min(datetime);
quit;
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