BookmarkSubscribeRSS Feed
🔒 This topic is solved and locked. Need further help from the community? Please sign in and ask a new question.
Anon
Calcite | Level 5

Hi,

This seems like something that must have been dealt with before, but I can't find any information related with the problem.

Taking the example from the SAS Language Dictionary to illustrate the use of the INDEX Function, if I run the following code, everything goes fine: the value of x is set to 10.

data _null_;

  a='ABC.DEF (X=Y)';

  b='X=Y';

  x=index(a,b);

  put x;

run;

However, if I add as the very first statement a LENGTH statement for the variable b, assigning it a declared length of 4 (or higher), then running this code returns a value of 0 for x:

data _null_;

  length b $ 4;

  a='ABC.DEF (X=Y)';

  b='X=Y';

  x=index(a,b);

  put x;

run;

Can anyone explain me why this happens, and how I can search for b in a if the declared length of b exceeds its actual length?

Thanks in advance,

-iwin

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

Many character operations pad variables to the max length, which appears to be the case here.

Use

x=index(a, strip(b));

View solution in original post

3 REPLIES 3
ballardw
Super User

Many character operations pad variables to the max length, which appears to be the case here.

Use

x=index(a, strip(b));

LarryWorley
Fluorite | Level 6

index function apparently does not trim trailing blanks from the value of a variable used as a parameter. That behavior is probably what should be expected.

In your first step, the data compiletr creates b with a length of 3 and there are no blanks assigned in it; so index works as expected.

When you define a length of 4 or more to b, the value used in index is right padded with blanks.  So when length = 5, the string 'X=Y  ' is what the index function sees.

You can test this by adding an explicit blank in your first case.  Index will not find the string.  Or by using compress or trim functions on b within the index function in the second example.

Anon
Calcite | Level 5

Thanks a lot for the fast responses.

They have been very helpful.

sas-innovate-2024.png

Join us for SAS Innovate April 16-19 at the Aria in Las Vegas. Bring the team and save big with our group pricing for a limited time only.

Pre-conference courses and tutorials are filling up fast and are always a sellout. Register today to reserve your seat.

 

Register now!

How to Concatenate Values

Learn how use the CAT functions in SAS to join values from multiple variables into a single value.

Find more tutorials on the SAS Users YouTube channel.

Click image to register for webinarClick image to register for webinar

Classroom Training Available!

Select SAS Training centers are offering in-person courses. View upcoming courses for:

View all other training opportunities.

Discussion stats
  • 3 replies
  • 815 views
  • 2 likes
  • 3 in conversation