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Insert more than one space into character variable

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Insert more than one space into character variable

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Hi all,

 

I have string value:

 

 

Cohort 9 / 7 mg/kg

 

and have to add 3 more empty spaces between slash and 6, like this one:

 

Cohort 9 /     7 mg/kg

 

What is the best solution for the case? Transword and simple concatination are not working.


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‎10-18-2017 08:49 AM
Super User
Posts: 7,854

Re: Insert more than one space into character variable

Posted in reply to DmytroYermak

Straight forward:

data test;
length string $30;
string = 'Cohort 9 / 7 mg/kg';
string = substr(string,1,indexc(string,'/')+1) !! '   ' !! substr(string,indexc(string,'/')+2);
run;
---------------------------------------------------------------------------------------------
Maxims of Maximally Efficient SAS Programmers

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‎10-18-2017 08:49 AM
Super User
Posts: 7,854

Re: Insert more than one space into character variable

Posted in reply to DmytroYermak

Straight forward:

data test;
length string $30;
string = 'Cohort 9 / 7 mg/kg';
string = substr(string,1,indexc(string,'/')+1) !! '   ' !! substr(string,indexc(string,'/')+2);
run;
---------------------------------------------------------------------------------------------
Maxims of Maximally Efficient SAS Programmers
Frequent Contributor
Posts: 142

Re: Insert more than one space into character variable

Posted in reply to KurtBremser
Thank you for the quick reply!
Regular Contributor
Posts: 237

Re: Insert more than one space into character variable

Posted in reply to DmytroYermak

The name of the function is tranwrd not transword.

 

string2=tranwrd(string,"/ ","/   "); /*works*/

Frequent Contributor
Posts: 142

Re: Insert more than one space into character variable

Thank you!
Super User
Posts: 11,343

Re: Insert more than one space into character variable

Posted in reply to DmytroYermak

Remember if you are attempting to do this with the source variable as the target variable, insert in place as it were, the length of the variable better be long enough to accept the additional characters or you may get truncation.

 

See this slight modification of the solution to demonstrate:

data test;
length string $19;
string = 'Cohort 9 / 7 mg/kg';
string = substr(string,1,indexc(string,'/')+1) !! '   ' !! substr(string,indexc(string,'/')+2);
run;
☑ This topic is solved.

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