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DmytroYermak
Lapis Lazuli | Level 10

Hi all,

 

I have string value:

 

 

Cohort 33 / 0.1 mg/kg

 

and have to add 3 more empty spaces between slash and 6, like this one:

 

Cohort 39 /   0.2 mg/kg

 

What is the best solution for the case? Transword and simple concatination are not working.

 
1 ACCEPTED SOLUTION

Accepted Solutions
Kurt_Bremser
Super User

Straight forward:

data test;
length string $30;
string = 'Cohort 9 / 7 mg/kg';
string = substr(string,1,indexc(string,'/')+1) !! '   ' !! substr(string,indexc(string,'/')+2);
run;

View solution in original post

5 REPLIES 5
Kurt_Bremser
Super User

Straight forward:

data test;
length string $30;
string = 'Cohort 9 / 7 mg/kg';
string = substr(string,1,indexc(string,'/')+1) !! '   ' !! substr(string,indexc(string,'/')+2);
run;
DmytroYermak
Lapis Lazuli | Level 10
Thank you for the quick reply!
gamotte
Rhodochrosite | Level 12

The name of the function is tranwrd not transword.

 

string2=tranwrd(string,"/ ","/   "); /*works*/

DmytroYermak
Lapis Lazuli | Level 10
Thank you!
ballardw
Super User

Remember if you are attempting to do this with the source variable as the target variable, insert in place as it were, the length of the variable better be long enough to accept the additional characters or you may get truncation.

 

See this slight modification of the solution to demonstrate:

data test;
length string $19;
string = 'Cohort 9 / 7 mg/kg';
string = substr(string,1,indexc(string,'/')+1) !! '   ' !! substr(string,indexc(string,'/')+2);
run;

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