Dear Experts
%let XTEMPLIST = BA EN CO CA SV IN UT TRA;
proc iml;
s="&xtemplist";
delims = ' ';
n = countw(s, delims);
xtemplist1 = scan(s, 1:3, delims);
xtemplist2 = scan(s, 4:n, delims);
print xtemplist1;
call symput("t",xtemplist1);
call symput("t1",xtemplist2);
quit;
%put &t;
%put &t1;
>> t-->only CO is displayed. How to get BA EN CO?
t1->>TRA is displayed. How to get CA SV IN UT TRA?
Thank you for your help
:LL
Here's a way that keeps all the processing under the control of macro language.
%let XTEMPLIST = BA EN CO CA SV IN UT TRA;
%macro split (n=3);
%GLOBAL XTEMPLIST1 XTEMPLIST2;
%let xtemplist1=;
%local i;
%do i=1 %to &n;
%let xtemplist1 = &xtemplist1 %scan(&xtemplist, &i);
%end;
%let xtemplist2 = %substr(xtemplist, %length(&xtemplist1) + 1);
%mend split;
%split (n=3)
Because of the %do loop, you will need to define a macro. On the other hand, you gain the advantage of being able to control how many words are selected into the first variable.
Here's a way that keeps all the processing under the control of macro language.
%let XTEMPLIST = BA EN CO CA SV IN UT TRA;
%macro split (n=3);
%GLOBAL XTEMPLIST1 XTEMPLIST2;
%let xtemplist1=;
%local i;
%do i=1 %to &n;
%let xtemplist1 = &xtemplist1 %scan(&xtemplist, &i);
%end;
%let xtemplist2 = %substr(xtemplist, %length(&xtemplist1) + 1);
%mend split;
%split (n=3)
Because of the %do loop, you will need to define a macro. On the other hand, you gain the advantage of being able to control how many words are selected into the first variable.
HoHo. You are doing this under IML code. You really want do this via IML ?
%let XTEMPLIST = BA EN CO CA SV IN UT TRA;
proc iml;
s="&xtemplist";
delims = ' ';
n = countw(s, delims);
xtemplist1 = scan(s, 1:3, delims);
xtemplist2 = scan(s, 4:n, delims);
print xtemplist1;
call symput("t",rowcat(xtemplist1+' '));
call symput("t1",rowcat(xtemplist2+' '));
quit;
%put &t;
%put &t1;
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