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sfmeier
Obsidian | Level 7

In a macro I am using the code
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%SYSFUNC(catx(_,&number ,%SYSFUNC(Intnx(qtr, &dvar, 0, end), DDMMYYP10.)))

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to create the output

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5_30.06.2013

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How can I create a dynamic leading zero?

1 ACCEPTED SOLUTION

Accepted Solutions
data_null__
Jade | Level 19

Looks like CATX is treating the number like a number.  You don't need CATX.

 

405 %let number=5;

406 %let dvar=%sysfunc(today());

407 %PUT NOTE: %sysfunc(putN(&number,z2))_%SYSFUNC(Intnx(qtr, &dvar, 0, end), DDMMYYP10.);

NOTE: 05_30.06.2012

View solution in original post

5 REPLIES 5
Astounding
PROC Star

Try replacing &number with:

%sysfunc(putn(&number, z2))

Messy, but it should work.

This assumes that &number is always less than 100, and you only want a leading zero when &number < 10.

sfmeier
Obsidian | Level 7

I tried exactly that, but it does not work 😞

Astounding
PROC Star

OK, you actually made me test my code.  It does work for me.  There are subtle parts of the syntax, such as PUTN instead of PUT, and no period at the end of the format name.  Can you post what you coded, and the results?

This is what worked:

%let n=5;

%let newn = %sysfunc(putn(&n, z2));

data_null__
Jade | Level 19

Looks like CATX is treating the number like a number.  You don't need CATX.

 

405 %let number=5;

406 %let dvar=%sysfunc(today());

407 %PUT NOTE: %sysfunc(putN(&number,z2))_%SYSFUNC(Intnx(qtr, &dvar, 0, end), DDMMYYP10.);

NOTE: 05_30.06.2012

sfmeier
Obsidian | Level 7

Ok, cool, thx! It works perfectly without catx... 🙂

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