Hello,
I wanted to create a dataset called timestamps that lists the last day of each month of the preceding 6 months. My solution for this is:
DATA timestamps;
d = today();
format d date9.;
DO i=0 TO 5;
d = intnx('month',d,-i)-1;
output;
END;
run;
DATA timestamps;
d = today();
format d date9.;
d = intnx('month',d,-1)-1;
run;
gives: 31MAY2017At a guess your changing the variable your working on, try:
data timestamps; d = today(); format d dt date9.; do i=0 to 5; dt=intnx('month',d,-i)-1; output; end; run;
At a guess your changing the variable your working on, try:
data timestamps; d = today(); format d dt date9.; do i=0 to 5; dt=intnx('month',d,-i)-1; output; end; run;
Don't miss out on SAS Innovate - Register now for the FREE Livestream!
Can't make it to Vegas? No problem! Watch our general sessions LIVE or on-demand starting April 17th. Hear from SAS execs, best-selling author Adam Grant, Hot Ones host Sean Evans, top tech journalist Kara Swisher, AI expert Cassie Kozyrkov, and the mind-blowing dance crew iLuminate! Plus, get access to over 20 breakout sessions.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.