Hi ,
I need to calculate in the end of the month day (e.i. 30,31,28,29) . Does anybody has any idea ?
Thanks
That's what I am looking for. Thanks for your help !!
You didn't indicate anything about your data. If they are just date fields and you want to know how many days were in the month represented by the dates you could use something like:
data have;
input havedate date9.;
format havedate date9.;
days_in_month=day(intnx('month',havedate,0,'e'));
cards;
03OCT2012
;
Exactly the same:
data have;
input date mmddyy10.;
format date mmddyy10.;
cards;
01/23/2012
02/04/2012
09/21/2012
;
data want;
set have;
day_at_end_of_month=day(intnx('month',date,0,'e'));
proc print;run;
Join us for SAS Innovate April 16-19 at the Aria in Las Vegas. Bring the team and save big with our group pricing for a limited time only.
Pre-conference courses and tutorials are filling up fast and are always a sellout. Register today to reserve your seat.
Learn how use the CAT functions in SAS to join values from multiple variables into a single value.
Find more tutorials on the SAS Users YouTube channel.