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Defining a Password by Characters in File Name

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Frequent Contributor
Posts: 99

Defining a Password by Characters in File Name

Hi all--

This may be a tricky question.

I use a Macro which password protects xml files. The macro %includeds a .vbs program.

options noxsync noxwait;

%include "X:\Programs\convert.sas";

%convert_files(default=X:\Datasets\Scores,ext=xml,password=test);

When the program runs it password protects every file in the folder with the same password -- in the case above "test. I need to change this so the password is different for every file.

The password starts with the letters ORE and then the code which is the first three characters in the file name.  

For file :

"700 FY13  Report.xml" The password needs to be ORE700

For file:

"B06 FY13  Report.xml" The password needs to be OREB06

For file:

"J10 FY13 Q1  Report.xml" The password needs to be OREJ10

Is there a way to read the first three characters of a file name and then use those characters in the password?

You feedback is appreciated!

Respected Advisor
Posts: 3,887

Re: Defining a Password by Characters in File Name

You don't show us your code so it's a bit hard to give you a concrete answer.

On a general level: Wouldn't a substring() function with the filename as source string give you what you need? ... substrn(scan("B06 FY13  Report.xml",-2,'/\.'),1,3)

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