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scb
Obsidian | Level 7 scb
Obsidian | Level 7

In the following code, i can get the answer for period1, but why I can't get the desired period for period2 but only got date back to 1960.  Please help, thanks.

 

%LET RUNDATE = '01OCT2016'D;

 

DATA _NULL_;
CALL SYMPUT("PERIOD1",PUT(INTNX('MONTH',&RUNDATE,-1,'E'),DATE9.));
CALL SYMPUT("PERIOD2",PUT(INTNX('MONTH',&RUNDATE,-1,'E'),DATETIME24.));
RUN;

 

%PUT &PERIOD1;
%PUT &PERIOD2;

 

 

1 ACCEPTED SOLUTION

Accepted Solutions
ballardw
Super User

What are you expecting for the result?

Date values are number of days from 1 Jan 1960

Datetime values are number of seconds from midnight 1 Jan 1960.

If you want a datetime value you need to do something to turn a date into datetime.

Perhaps this is close to what you want:

 

%LET RUNDATE = 01OCT2016;

DATA _NULL_;
CALL SYMPUT("PERIOD1",PUT(INTNX('MONTH',"&RUNDATE"d,-1,'E'),DATE9.));
CALL SYMPUT("PERIOD2",PUT(INTNX('dtMONTH',"&RUNDATE 00:00:00"dt,-1,'E'),DATETIME24.));
RUN;

%PUT &PERIOD1;
%PUT &PERIOD2;

View solution in original post

3 REPLIES 3
ballardw
Super User

What are you expecting for the result?

Date values are number of days from 1 Jan 1960

Datetime values are number of seconds from midnight 1 Jan 1960.

If you want a datetime value you need to do something to turn a date into datetime.

Perhaps this is close to what you want:

 

%LET RUNDATE = 01OCT2016;

DATA _NULL_;
CALL SYMPUT("PERIOD1",PUT(INTNX('MONTH',"&RUNDATE"d,-1,'E'),DATE9.));
CALL SYMPUT("PERIOD2",PUT(INTNX('dtMONTH',"&RUNDATE 00:00:00"dt,-1,'E'),DATETIME24.));
RUN;

%PUT &PERIOD1;
%PUT &PERIOD2;
scb
Obsidian | Level 7 scb
Obsidian | Level 7

It almost got what I wanted; but may i know why the datetime was 30SEP2016:23:59:59 instead of 30SEP2016:00:00:00? Any idea why?

ballardw
Super User

Your -1 subtracts one second. I left that in because you never showed what you expected the result to actually be.

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