Convert Integer Datetime to Datetime format

[jei]

Hi,

May I ask how can I convert the datetime data which is an integer into datetime format? I've tried many options but still it shows the same or the data becomes periods (.....).

These are my data:

lngIndatetime
20170331104215
20170401154920
20170401190015
20170401190014
20170402123848
20170402162202
20170402162202
20170405051751
20170405051437
20170405054608

I would like to look like 20170405054608 = April 5, 2017 05:46:08.

Thank you!

[PeterClemmensen]

Is lngIndatetime character or numeric?

[jei]

Hi @PeterClemmensen

lngIndatetime is character.

[Kurt_Bremser]

Use substr() to extract relevant parts of your character string, input() to convert to numeric, and dhms() to convert to a datetime value:

data have;
input lngIndatetime :$14.;
cards;
20170331104215
20170401154920
20170401190015
20170401190014
20170402123848
20170402162202
20170402162202
20170405051751
20170405051437
20170405054608
;
run;

data want;
set have;
lngIndatetime_num = dhms(
  input(substr(lngIndatetime,1,8),yymmdd8.),
  input(substr(lngIndatetime,9,2),2.),
  input(substr(lngIndatetime,11,2),2.),
  input(substr(lngIndatetime,13,2),2.)
);
format lngIndatetime_num datetime19.;
run;

[jei]

Hi @Kurt_Bremser,

I'm getting error when running the given code. The data is in numeric format.

Thank you!

[PeterClemmensen]

data have;
input lngIndatetime $15.;
datalines;
20170331104215
20170401154920
20170401190015
20170401190014
20170402123848
20170402162202
20170402162202
20170405051751
20170405051437
20170405054608
;

data want(drop=_dt);
	set have;
	_dt = cats(substr(lngIndatetime,1,8),"T",substr(lngIndatetime,9,6));
	dt = input(_dt, b8601dt15.);
	format dt datetime20.;
run;

[Kurt_Bremser]

---

@jei wrote:
Hi @Kurt_Bremser,

I'm getting error when running the given code. The data is in numeric format.

Thank you!

---

PLEASE POST THE ******* LOG WHEN REPORTING AN ERROR!!!

Just to quote yourself:

"

Hi @draycut

lngIndatetime is character."

Please make up your mind.

Post your real data in a data step, as described a gazillion times on this forum.

[Kurt_Bremser]

Hi @draycut

lngIndatetime is character."

Please make up your mind.

Post your real data in a data step, as described a gazillion times on this forum.

[PeterClemmensen]

Dirty correction to my previous code should to

data have;
input lngIndatetime;
format lngIndatetime 20.;
datalines;
20170331104215
20170401154920
20170401190015
20170401190014
20170402123848
20170402162202
20170402162202
20170405051751
20170405051437
20170405054608
;

data want(drop=_dt CharDT);
	set have;
	CharDT = put(20170331104215, 14.);
	_dt = cats(substr(CharDT,1,8),"T",substr(CharDT,9,6));
	dt = input(_dt, b8601dt15.);
	format dt datetime20.;
run;

[ChrisBrooks · Accepted solution]

I think the final substr is wrong - should be

data have;
input lngIndatetime;
format lngIndatetime 20.;
datalines;
20170331104215
20170401154920
20170401190015
20170401190014
20170402123848
20170402162202
20170402162202
20170405051751
20170405051437
20170405054608
;

data want(drop=_dt CharDT);
	set have;
	CharDT = put(20170331104215, 14.);
	_dt = cats(substr(CharDT,1,8),"T",substr(CharDT,9,6));
	dt = input(_dt, b8601dt15.);
	format dt datetime20.;
run;

[PeterClemmensen]

Of course. Good catch @ChrisBrooks 🙂