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Walternate
Obsidian | Level 7

Hi everyone,

I have data that look like this:

ID       Date

1        01/13

1        04/13

1        05/13

1        09/13

2        03/13

2        04/13

What I need is to determine the amount of time between a person's first date and their second date, their third date and their fourth date, their fifth/sixth, etc. Not every participant has the same number of dates.

Any help is much appreciated.

Thanks!

1 ACCEPTED SOLUTION

Accepted Solutions
PaigeMiller
Diamond | Level 26

If the dates are character strings, I would convert the date values to actual numbers, and display then with the MMYY. format.

Once that is done, you could compute the delta between two consecutive times via the LAG function and the INTCK function

data oink;

     set whatever;

     by id;

     prevdate=lag(date);

     if not first.id then delta=intck('month',date,prevdate);

run;

--
Paige Miller

View solution in original post

1 REPLY 1
PaigeMiller
Diamond | Level 26

If the dates are character strings, I would convert the date values to actual numbers, and display then with the MMYY. format.

Once that is done, you could compute the delta between two consecutive times via the LAG function and the INTCK function

data oink;

     set whatever;

     by id;

     prevdate=lag(date);

     if not first.id then delta=intck('month',date,prevdate);

run;

--
Paige Miller

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