<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#" xmlns:taxo="http://purl.org/rss/1.0/modules/taxonomy/" version="2.0">
  <channel>
    <title>topic Wilcoxon signed rank test (exact distributions) in Statistical Procedures</title>
    <link>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129606#M6810</link>
    <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;&lt;BR /&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;For n &amp;lt;= 20, proc univariate uses the exact distribution to compute the significance of S, but what exactly happens when there are tied ranks within the small dataset?&amp;nbsp; I've read all 3 references (Iman, Conover, and Lehmann), but none of them really explain what happens when ties occur with a small sample (n &amp;lt;= 20) with the exact distribution.&amp;nbsp; An example is below...&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; Consider the data:&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; Grp1&amp;nbsp;&amp;nbsp; Grp2&amp;nbsp; Diff&amp;nbsp;&amp;nbsp; Rank&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .32&amp;nbsp;&amp;nbsp;&amp;nbsp; .39&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.07&amp;nbsp;&amp;nbsp;&amp;nbsp; 3.5&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .4&amp;nbsp;&amp;nbsp;&amp;nbsp; .47&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.07&amp;nbsp;&amp;nbsp;&amp;nbsp; 3.5&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .11&amp;nbsp;&amp;nbsp;&amp;nbsp; .11&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 0.00&amp;nbsp;&amp;nbsp;&amp;nbsp; ---&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .47&amp;nbsp;&amp;nbsp;&amp;nbsp; .43&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 0.04&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 1&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .32&amp;nbsp;&amp;nbsp;&amp;nbsp; .42&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.10&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 5&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .35&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 0.05&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 2&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .32&amp;nbsp;&amp;nbsp;&amp;nbsp; .43&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.11&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 6&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .63&amp;nbsp;&amp;nbsp;&amp;nbsp; .98&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.35&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 8&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .5&amp;nbsp;&amp;nbsp;&amp;nbsp; .86&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.36&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 9&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .6&amp;nbsp;&amp;nbsp;&amp;nbsp; .79&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.19&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 7&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&amp;nbsp; &lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;Sum of ranks for positive differences (ri+) = 3&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; &lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;Given that the ranks are {1, 2, 3.5, 3.5, 5, 6, 7, 8, 9}, the only ways to get a sum of ranks that is less than or equal to 3 is for the set of positive ranks to be one of:&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;Set&amp;nbsp;&amp;nbsp;&amp;nbsp; Sum&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {}&amp;nbsp;&amp;nbsp;&amp;nbsp; = 0&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; {1}&amp;nbsp;&amp;nbsp; = 1&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; {2}&amp;nbsp;&amp;nbsp; = 2&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; {1,2} = 3&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&amp;nbsp; &lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;So, there are 4 configurations on the left-hand side extreme and 4 on the right.&amp;nbsp; Thus, the p-value should be 8/2^9 = 8/512 = 0.0156. However, SAS reports p=10/512 = 0.0195.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&lt;SPAN style="color: black;"&gt;Perhaps, SAS is saying that &lt;/SPAN&gt;&lt;SPAN style="color: black;"&gt;{3.5} is either {3} or {4} with ½ probability.&amp;nbsp; Thus, this would be ½ more cases.&amp;nbsp; Since there are two ranks of 3.5, each could be {3} with ½ probability and thus there would be a total of 5 configurations on the left extreme and 5 on the right?&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; &lt;SPAN style="color: black;"&gt;Set&amp;nbsp;&amp;nbsp;&amp;nbsp; Sum&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {}&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; = 0 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {1}&amp;nbsp;&amp;nbsp;&amp;nbsp; = 1 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {2}&amp;nbsp;&amp;nbsp;&amp;nbsp; = 2 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {1,2} = 3 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {3.5} = 3 with&amp;nbsp; 50% probability&amp;nbsp; = 0.5 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; &lt;SPAN style="color: black;"&gt;{3.5} = 3 with&amp;nbsp; 50% probability&amp;nbsp; = 0.5 case&lt;/SPAN&gt;&lt;SPAN style="color: black;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; ---------&lt;/SPAN&gt;&lt;SPAN style="color: black;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 5.0 cases&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-size: 10pt; font-family: arial,helvetica,sans-serif;"&gt;If you know how SAS is computing the exact p-value with ties (all possible combinations of the sum of ranks less than or equal to the sum of positive ranks) or know where a 'useful' reference might be, please let me know.&amp;nbsp; Thanks in advance!!&lt;/SPAN&gt;&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
    <pubDate>Wed, 30 May 2012 19:31:51 GMT</pubDate>
    <dc:creator>trharris14</dc:creator>
    <dc:date>2012-05-30T19:31:51Z</dc:date>
    <item>
      <title>Wilcoxon signed rank test (exact distributions)</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129606#M6810</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;&lt;BR /&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;For n &amp;lt;= 20, proc univariate uses the exact distribution to compute the significance of S, but what exactly happens when there are tied ranks within the small dataset?&amp;nbsp; I've read all 3 references (Iman, Conover, and Lehmann), but none of them really explain what happens when ties occur with a small sample (n &amp;lt;= 20) with the exact distribution.&amp;nbsp; An example is below...&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; Consider the data:&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; Grp1&amp;nbsp;&amp;nbsp; Grp2&amp;nbsp; Diff&amp;nbsp;&amp;nbsp; Rank&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .32&amp;nbsp;&amp;nbsp;&amp;nbsp; .39&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.07&amp;nbsp;&amp;nbsp;&amp;nbsp; 3.5&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .4&amp;nbsp;&amp;nbsp;&amp;nbsp; .47&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.07&amp;nbsp;&amp;nbsp;&amp;nbsp; 3.5&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .11&amp;nbsp;&amp;nbsp;&amp;nbsp; .11&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 0.00&amp;nbsp;&amp;nbsp;&amp;nbsp; ---&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .47&amp;nbsp;&amp;nbsp;&amp;nbsp; .43&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 0.04&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 1&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .32&amp;nbsp;&amp;nbsp;&amp;nbsp; .42&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.10&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 5&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .35&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .3&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 0.05&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 2&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .32&amp;nbsp;&amp;nbsp;&amp;nbsp; .43&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.11&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 6&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .63&amp;nbsp;&amp;nbsp;&amp;nbsp; .98&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.35&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 8&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .5&amp;nbsp;&amp;nbsp;&amp;nbsp; .86&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.36&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 9&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; .6&amp;nbsp;&amp;nbsp;&amp;nbsp; .79&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; -0.19&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 7&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&amp;nbsp; &lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;Sum of ranks for positive differences (ri+) = 3&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; &lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;Given that the ranks are {1, 2, 3.5, 3.5, 5, 6, 7, 8, 9}, the only ways to get a sum of ranks that is less than or equal to 3 is for the set of positive ranks to be one of:&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;Set&amp;nbsp;&amp;nbsp;&amp;nbsp; Sum&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {}&amp;nbsp;&amp;nbsp;&amp;nbsp; = 0&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; {1}&amp;nbsp;&amp;nbsp; = 1&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; {2}&amp;nbsp;&amp;nbsp; = 2&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt; {1,2} = 3&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&amp;nbsp; &lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;So, there are 4 configurations on the left-hand side extreme and 4 on the right.&amp;nbsp; Thus, the p-value should be 8/2^9 = 8/512 = 0.0156. However, SAS reports p=10/512 = 0.0195.&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&lt;SPAN style="color: black;"&gt;Perhaps, SAS is saying that &lt;/SPAN&gt;&lt;SPAN style="color: black;"&gt;{3.5} is either {3} or {4} with ½ probability.&amp;nbsp; Thus, this would be ½ more cases.&amp;nbsp; Since there are two ranks of 3.5, each could be {3} with ½ probability and thus there would be a total of 5 configurations on the left extreme and 5 on the right?&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; &lt;SPAN style="color: black;"&gt;Set&amp;nbsp;&amp;nbsp;&amp;nbsp; Sum&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {}&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; = 0 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {1}&amp;nbsp;&amp;nbsp;&amp;nbsp; = 1 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {2}&amp;nbsp;&amp;nbsp;&amp;nbsp; = 2 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {1,2} = 3 with 100% probability = 1.0 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; {3.5} = 3 with&amp;nbsp; 50% probability&amp;nbsp; = 0.5 case&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="font-family: arial,helvetica,sans-serif; font-size: 10pt;"&gt;&amp;nbsp; &lt;SPAN style="color: black;"&gt;{3.5} = 3 with&amp;nbsp; 50% probability&amp;nbsp; = 0.5 case&lt;/SPAN&gt;&lt;SPAN style="color: black;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; ---------&lt;/SPAN&gt;&lt;SPAN style="color: black;"&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; &lt;BR /&gt;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp; 5.0 cases&lt;/SPAN&gt;&lt;/SPAN&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;SPAN style="color: black; font-size: 10pt; font-family: arial,helvetica,sans-serif;"&gt;If you know how SAS is computing the exact p-value with ties (all possible combinations of the sum of ranks less than or equal to the sum of positive ranks) or know where a 'useful' reference might be, please let me know.&amp;nbsp; Thanks in advance!!&lt;/SPAN&gt;&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Wed, 30 May 2012 19:31:51 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129606#M6810</guid>
      <dc:creator>trharris14</dc:creator>
      <dc:date>2012-05-30T19:31:51Z</dc:date>
    </item>
    <item>
      <title>Re: Wilcoxon signed rank test (exact distributions)</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129607#M6811</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;This SUGI 1994 paper contains a macro that uses the DATA step to reproduce the WSR test, so you ought to be able to see exactly what happens for tied values.&lt;/P&gt;&lt;P&gt;&lt;A href="http://www.sascommunity.org/sugi/SUGI94/Sugi-94-172%20Tian.pdf" title="http://www.sascommunity.org/sugi/SUGI94/Sugi-94-172%20Tian.pdf"&gt;http://www.sascommunity.org/sugi/SUGI94/Sugi-94-172%20Tian.pdf&lt;/A&gt;&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Wed, 30 May 2012 23:14:15 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129607#M6811</guid>
      <dc:creator>Rick_SAS</dc:creator>
      <dc:date>2012-05-30T23:14:15Z</dc:date>
    </item>
    <item>
      <title>Re: Wilcoxon signed rank test (exact distributions)</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129608#M6812</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;Thanks for the paper Rick, but it doesn't really tell how SAS calculates the exact p-values, just shows an attached file in the macro code (WSRtable.dat).&amp;nbsp; Thanks for your help though!!&amp;nbsp; Have a great day!&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Thu, 31 May 2012 16:27:48 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129608#M6812</guid>
      <dc:creator>trharris14</dc:creator>
      <dc:date>2012-05-31T16:27:48Z</dc:date>
    </item>
    <item>
      <title>Re: Wilcoxon signed rank test (exact distributions)</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129609#M6813</link>
      <description>&lt;HTML&gt;&lt;HEAD&gt;&lt;/HEAD&gt;&lt;BODY&gt;&lt;P&gt;For details of exact test calculation methods, you might have to look in the references within :&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;&lt;A href="http://support.sas.com/documentation/cdl/en/statug/63962/HTML/default/viewer.htm#statug_npar1way_a0000000203.htm"&gt;http://support.sas.com/documentation/cdl/en/statug/63962/HTML/default/viewer.htm#statug_npar1way_a0000000203.htm&lt;/A&gt;&lt;/P&gt;&lt;P&gt;&lt;/P&gt;&lt;P&gt;PG&lt;/P&gt;&lt;/BODY&gt;&lt;/HTML&gt;</description>
      <pubDate>Thu, 31 May 2012 18:01:54 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/Wilcoxon-signed-rank-test-exact-distributions/m-p/129609#M6813</guid>
      <dc:creator>PGStats</dc:creator>
      <dc:date>2012-05-31T18:01:54Z</dc:date>
    </item>
  </channel>
</rss>

