https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775633#M37980 In the second picture. there are only two variables ,when delete one of both ,you can't get Alpha (you can't calculate Alpha by only one variable). Thu, 21 Oct 2021 12:53:13 GMT Ksharp 2021-10-21T12:53:13Z https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775527#M37973 <DIV class=""><DIV class=""><DIV class="">Hi. I want to calculate the <STRONG>Cronbach's Alpha</STRONG> for a 3-item 5-point Likert scale. I did so but I have a question.</DIV><DIV class="">1- I calculated Cronbach's Alpha and it was 0.852 but one variable seemed to reduce this value so I decided to remove it. photo below:&nbsp;<BR /><BR /><span class="lia-inline-image-display-wrapper lia-image-align-center" image-alt="11111111.PNG" style="width: 697px;"><img src="https://communities.sas.com/t5/image/serverpage/image-id/64910iF46450E40746CBF9/image-dimensions/697x553?v=v2" width="697" height="553" role="button" title="11111111.PNG" alt="11111111.PNG" /></span>&nbsp;</DIV><DIV class="">2- Removing that item left me with 2 items/variables. The new Cronbach's Alpha is <STRONG>0.943</STRONG>&nbsp;.. this was already shown in the first table (first photo) but I wanted to run the code using the two items so I can create a <U>new table&nbsp;just to show the difference.&nbsp;</U></DIV><DIV class="">3- I ran the code and the output is shown in the photo below.</DIV></DIV></DIV><DIV class=""><DIV class=""><DIV class=""><span class="lia-inline-image-display-wrapper lia-image-align-center" image-alt="222222222.PNG" style="width: 576px;"><img src="https://communities.sas.com/t5/image/serverpage/image-id/64911i13054B652B3EC4E0/image-dimensions/576x363?v=v2" width="576" height="363" role="button" title="222222222.PNG" alt="222222222.PNG" /></span><DIV class="">I understand that I can compute Cronbach's Alpha for two items as long as they are highly correlated and this condition is met.</DIV><DIV class=""><STRONG>My question</STRONG>: Is there an explanation as to why Cronbach's Alpha was not calculated and instead was shown as a missing value (second photo)?</DIV></DIV></DIV></DIV> Wed, 20 Oct 2021 21:46:28 GMT https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775527#M37973 sumah 2021-10-20T21:46:28Z https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775633#M37980 In the second picture. there are only two variables ,when delete one of both ,you can't get Alpha (you can't calculate Alpha by only one variable). Thu, 21 Oct 2021 12:53:13 GMT https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775633#M37980 Ksharp 2021-10-21T12:53:13Z https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775668#M37982 <P>oh i completely missed that. thank you so much.&nbsp;</P> Thu, 21 Oct 2021 15:02:56 GMT https://communities.sas.com/t5/Statistical-Procedures/Cronbach-s-Alpha/m-p/775668#M37982 sumah 2021-10-21T15:02:56Z