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    <title>topic Linear combination using classical linear discriminate in Statistical Procedures</title>
    <link>https://communities.sas.com/t5/Statistical-Procedures/Linear-combination-using-classical-linear-discriminate/m-p/65567#M3115</link>
    <description>I have two bivariate variables with means and variances differ by group (diseased, non-diseased). No dependent variable (binary variables). I would like to make a linear combination using classical linear discriminate.    &lt;BR /&gt;
X1D ….N(0.5, 2), X2D ….N(0.5, 2) &lt;BR /&gt;
X1N ….N(0, 1), X2N ….N(0, 1)&lt;BR /&gt;
&lt;BR /&gt;
Where D stands for diseased and N is non-diseased.&lt;BR /&gt;
Any helps PLZ&lt;BR /&gt;
Thanks..</description>
    <pubDate>Mon, 08 Mar 2010 13:09:23 GMT</pubDate>
    <dc:creator>1234567</dc:creator>
    <dc:date>2010-03-08T13:09:23Z</dc:date>
    <item>
      <title>Linear combination using classical linear discriminate</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/Linear-combination-using-classical-linear-discriminate/m-p/65567#M3115</link>
      <description>I have two bivariate variables with means and variances differ by group (diseased, non-diseased). No dependent variable (binary variables). I would like to make a linear combination using classical linear discriminate.    &lt;BR /&gt;
X1D ….N(0.5, 2), X2D ….N(0.5, 2) &lt;BR /&gt;
X1N ….N(0, 1), X2N ….N(0, 1)&lt;BR /&gt;
&lt;BR /&gt;
Where D stands for diseased and N is non-diseased.&lt;BR /&gt;
Any helps PLZ&lt;BR /&gt;
Thanks..</description>
      <pubDate>Mon, 08 Mar 2010 13:09:23 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/Linear-combination-using-classical-linear-discriminate/m-p/65567#M3115</guid>
      <dc:creator>1234567</dc:creator>
      <dc:date>2010-03-08T13:09:23Z</dc:date>
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