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    <title>topic Re: randomized crossover design: one condition repeated twice, need to collapse into one condition in Statistical Procedures</title>
    <link>https://communities.sas.com/t5/Statistical-Procedures/randomized-crossover-design-one-condition-repeated-twice-need-to/m-p/579776#M28437</link>
    <description>&lt;P&gt;I'm no expert in randomized trials, but consider this:&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;In a double blind trial, you could be given 4 treatments, not knowing what they are. You are only told after initial analysis that treatments c and d were in fact the same. Knowing this you could then test the differences a - (c+d)/2 and b - (c+d)/2, after fitting your model, without having to manipulate your data or change your model.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;hth&lt;/P&gt;</description>
    <pubDate>Thu, 08 Aug 2019 03:02:17 GMT</pubDate>
    <dc:creator>PGStats</dc:creator>
    <dc:date>2019-08-08T03:02:17Z</dc:date>
    <item>
      <title>randomized crossover design: one condition repeated twice, need to collapse into one condition</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/randomized-crossover-design-one-condition-repeated-twice-need-to/m-p/579767#M28436</link>
      <description>&lt;P&gt;&lt;SPAN&gt;I am trying to figure out the appropriate method of collapsing two of four session conditions for a randomized crossover trial.&amp;nbsp;&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;We had four session conditions (a, b, c, d) and unfortunately discovered that the same condition was provided twice and we technically only have three unique session conditions (a, b, c/d). For the two session conditions that are the same (c and d), we want to collapse them to create a single session condition (c/d). However, the order each participant/dyad received session conditions in was random i.e. participant 1 could have received treatments in this order: a, c, d, b and participant 2 could have received treatments in this order: c, b, d, a.&amp;nbsp;&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;My initial thought was to take the results from the two session conditions that were the same (c and d) and calculate the average, but I feel that is not the most appropriate method. We essentially have a session condition that was repeated and two session conditions that were not.&amp;nbsp;&lt;/SPAN&gt;&lt;BR /&gt;&lt;BR /&gt;&lt;SPAN&gt;Appreciate any advice!&lt;/SPAN&gt;&lt;/P&gt;</description>
      <pubDate>Wed, 07 Aug 2019 21:32:05 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/randomized-crossover-design-one-condition-repeated-twice-need-to/m-p/579767#M28436</guid>
      <dc:creator>hyunjeehale</dc:creator>
      <dc:date>2019-08-07T21:32:05Z</dc:date>
    </item>
    <item>
      <title>Re: randomized crossover design: one condition repeated twice, need to collapse into one condition</title>
      <link>https://communities.sas.com/t5/Statistical-Procedures/randomized-crossover-design-one-condition-repeated-twice-need-to/m-p/579776#M28437</link>
      <description>&lt;P&gt;I'm no expert in randomized trials, but consider this:&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;In a double blind trial, you could be given 4 treatments, not knowing what they are. You are only told after initial analysis that treatments c and d were in fact the same. Knowing this you could then test the differences a - (c+d)/2 and b - (c+d)/2, after fitting your model, without having to manipulate your data or change your model.&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;hth&lt;/P&gt;</description>
      <pubDate>Thu, 08 Aug 2019 03:02:17 GMT</pubDate>
      <guid>https://communities.sas.com/t5/Statistical-Procedures/randomized-crossover-design-one-condition-repeated-twice-need-to/m-p/579776#M28437</guid>
      <dc:creator>PGStats</dc:creator>
      <dc:date>2019-08-08T03:02:17Z</dc:date>
    </item>
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