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  <channel>
    <title>topic Re: How to select both duplicate IDs if a condition met in SAS Procedures</title>
    <link>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900801#M83069</link>
    <description>&lt;P&gt;You could use a PROC SQL subquery to find the (distinct?) IDs with records in 2023 and then pull all records matching those IDs.&amp;nbsp;&amp;nbsp;&lt;/P&gt;
&lt;PRE&gt;proc sql;
	select id, year
	from have
	where id in (select id
		     from have
	             where year=2023);
quit;&lt;/PRE&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
    <pubDate>Mon, 30 Oct 2023 20:15:08 GMT</pubDate>
    <dc:creator>antonbcristina</dc:creator>
    <dc:date>2023-10-30T20:15:08Z</dc:date>
    <item>
      <title>How to select both duplicate IDs if a condition met</title>
      <link>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900796#M83068</link>
      <description>&lt;P&gt;This should be an easy solution but could not figured it out. How to I select both duplicate IDs if year is associated with 2023?&lt;/P&gt;
&lt;P&gt;Have&lt;/P&gt;
&lt;TABLE width="148"&gt;
&lt;TBODY&gt;
&lt;TR&gt;
&lt;TD width="76"&gt;ID&lt;/TD&gt;
&lt;TD width="72"&gt;year&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;130177&lt;/TD&gt;
&lt;TD&gt;2021&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;130177&lt;/TD&gt;
&lt;TD&gt;2022&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;137939&lt;/TD&gt;
&lt;TD&gt;2021&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;137939&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;160200&lt;/TD&gt;
&lt;TD&gt;2022&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;160200&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;166898&lt;/TD&gt;
&lt;TD&gt;2020&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;166898&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;175553&lt;/TD&gt;
&lt;TD&gt;2022&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;175553&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;/TBODY&gt;
&lt;/TABLE&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;want:&lt;/P&gt;
&lt;TABLE width="148"&gt;
&lt;TBODY&gt;
&lt;TR&gt;
&lt;TD width="76"&gt;ID&lt;/TD&gt;
&lt;TD width="72"&gt;year&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;137939&lt;/TD&gt;
&lt;TD&gt;2021&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;137939&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;160200&lt;/TD&gt;
&lt;TD&gt;2022&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;160200&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;166898&lt;/TD&gt;
&lt;TD&gt;2020&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;166898&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;175553&lt;/TD&gt;
&lt;TD&gt;2022&lt;/TD&gt;
&lt;/TR&gt;
&lt;TR&gt;
&lt;TD&gt;175553&lt;/TD&gt;
&lt;TD&gt;2023&lt;/TD&gt;
&lt;/TR&gt;
&lt;/TBODY&gt;
&lt;/TABLE&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;
&lt;P&gt;data HAVE;&lt;BR /&gt;input ID year;&lt;BR /&gt;cards;&lt;BR /&gt;130177 2021&lt;BR /&gt;130177 2022&lt;BR /&gt;137939 2021&lt;BR /&gt;137939 2023&lt;BR /&gt;160200 2022&lt;BR /&gt;160200 2023&lt;BR /&gt;166898 2020&lt;BR /&gt;166898 2023&lt;BR /&gt;175553 2022&lt;BR /&gt;175553 2023&lt;BR /&gt;run;&lt;/P&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Mon, 30 Oct 2023 19:53:15 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900796#M83068</guid>
      <dc:creator>bijayadhikar</dc:creator>
      <dc:date>2023-10-30T19:53:15Z</dc:date>
    </item>
    <item>
      <title>Re: How to select both duplicate IDs if a condition met</title>
      <link>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900801#M83069</link>
      <description>&lt;P&gt;You could use a PROC SQL subquery to find the (distinct?) IDs with records in 2023 and then pull all records matching those IDs.&amp;nbsp;&amp;nbsp;&lt;/P&gt;
&lt;PRE&gt;proc sql;
	select id, year
	from have
	where id in (select id
		     from have
	             where year=2023);
quit;&lt;/PRE&gt;
&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Mon, 30 Oct 2023 20:15:08 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900801#M83069</guid>
      <dc:creator>antonbcristina</dc:creator>
      <dc:date>2023-10-30T20:15:08Z</dc:date>
    </item>
    <item>
      <title>Re: How to select both duplicate IDs if a condition met</title>
      <link>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900822#M83070</link>
      <description>Thanks for your time and prompt response!</description>
      <pubDate>Mon, 30 Oct 2023 21:53:49 GMT</pubDate>
      <guid>https://communities.sas.com/t5/SAS-Procedures/How-to-select-both-duplicate-IDs-if-a-condition-met/m-p/900822#M83070</guid>
      <dc:creator>bijayadhikar</dc:creator>
      <dc:date>2023-10-30T21:53:49Z</dc:date>
    </item>
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