topic SUBSTITUTE AN ARRAY FOR AN IF-THEN STATEMENT in SAS Procedures

SUBSTITUTE AN ARRAY FOR AN IF-THEN STATEMENT

TPayne — Wed, 19 Jun 2019 18:28:47 GMT

Hello,

I have a data set with variables that I want to compare using an array, but currently have an if-then statement.

Data set:

dtp1

dtp1src

dtp2

dtp2src

dtp3

dtp3src

dtp4

dtp4src

dtp5

dtp5src

dtp6

dtp6src

dtp7

dtp7src

dtp8

dtp8src

1/1/2016

2/22/2016

5/10/2016

7/19/2016

7/14/2017

5/10/2016

7/7/2016

5/1/2017

4/1/2016

4/5/2017

5/3/2017

3/9/2016

7/8/2016

7/20/2017

4/4/2016

7/11/2016

9/26/2016

4/24/2017

Each "src" column refers to the column before it (where dtp1src is the vaccination source for the dtp1 vaccination date). What I want to end up with is a error variable of any vaccination date (DTP1-DTP8) that does not have a source (DTP1SRC-DTP8SRC) and any source (DTP1-DTP8) that does not have a vaccination date (DTP1-DTP8). Below is the code I currently have. It works fine, but I feel like there is a more elegant way to flag these using an array/do loop. Any suggestions are greatly appreciated!

DATA CLEANING.DTP_ERROR;

SET CLEANING.VALID;
IF DTP1 NE . AND DTP1src=' ' OR DTP1=. AND DTP1SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP2 NE . AND DTP2src=' ' OR DTP2=. AND DTP2SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP3 NE . AND DTP3src=' ' OR DTP3=. AND DTP3SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP4 NE . AND DTP4src=' ' OR DTP4=. AND DTP4SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP5 NE . AND DTP5src=' ' OR DTP5=. AND DTP5SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP6 NE . AND DTP6src=' ' OR DTP6=. AND DTP6SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP7 NE . AND DTP7src=' ' OR DTP7=. AND DTP7SRC NE ' ' THEN ERROR= 'SOURCECHECK';
IF DTP8 NE . AND DTP8src=' ' OR DTP8=. AND DTP8SRC NE ' ' THEN ERROR= 'SOURCECHECK';
RUN;

Re: SUBSTITUTE AN ARRAY FOR AN IF-THEN STATEMENT

Reeza — Wed, 19 Jun 2019 18:52:34 GMT

Arrays are one of the easier SAS components. This tutorial goes through arrays and how to set it up. One is very close to your situation.

1. Declare 2 arrays, one for DTP series and one for DTP1src series.
2. Change the reference from the vairable to the array with an i
3. Wrap it in a loop.

And this would be infinitely easier if you had your data set in the long format previous compared to this wide format.

You can also look into NMISS() or CMISS() to count missing if that may help.

Re: SUBSTITUTE AN ARRAY FOR AN IF-THEN STATEMENT

Kurt_Bremser — Wed, 19 Jun 2019 18:55:54 GMT

data cleaning.dtp_error;
set cleaning.valid;
array dtp{8} dtp1-dtp8;
array dtpsrc{8} dtp1src dtp2src dtp3src dtp4src dtp5src dtp6src dtp7src dtp8src;
do i = 1 to 8;
  if dtp{i} ne . and dtpsrc{i} =' ' or dtp{i} = . and dtpsrc{i} ne ' ' then error = 'SOURCECHECK';
end;
run;

Re: SUBSTITUTE AN ARRAY FOR AN IF-THEN STATEMENT

Kurt_Bremser — Wed, 19 Jun 2019 19:01:57 GMT

And I strongly second @Reeza 's comment about reasonable data structures. With a properly structured dataset, the code would be simple as that, and you wouldn't waste space for all the missing values.

See Maxim 33: Intelligent data makes for intelligent programs.