topic Re: sas loop macro in SAS Procedures

sas loop macro

jack1078 — Mon, 06 Jul 2015 13:18:38 GMT

I all,

I have a problem. I do so as from a table with 100 rows bait a table with rows that have that condition. By turning the macro made sas erases and writes the new data set and then instead of 4 lines provided only one that comes out the end of the dataset.

%macro xxx ();

%do i=1 %to 24;

data _null_;

var="hour"||put(&i,z2.);

call symput('var',var);

run;

data control1;

set control;

%put &var;

if &var eq "AAA" or &var eq "BBB" or &var eq "CCC" then delete;

%end;

run;

%mend xxx;

%xxx;

thank's a lot

bie bie m

Re: sas loop macro

MadhuKorni — Mon, 06 Jul 2015 13:30:24 GMT

Hi Jack,

Can you be somewhat clear about the issue.

You closed the do loop inside the datastep block.

Re: sas loop macro

jack1078 — Mon, 06 Jul 2015 13:35:23 GMT

I have a table of 100 rows and 3 columns. who call hour01 hour02 hour03. I try to find in these three columns if data is different from "AAA", "BBB" and "CCC". If it is different then I write in a table. So if there are three lines that read "LLL" I find myself in the new table three lines.

Re: sas loop macro

Astounding — Mon, 06 Jul 2015 13:44:39 GMT

So far, there is no use for macros here. You could easily code:

data want;

set have;

if hour01 not in ('AAA', 'BBB', 'CCC') then output;

else if hour02 not in ('AAA', 'BBB', 'CCC') then output;

else if hour03 not in ('AAA', 'BBB', 'CCC') then output;

run;

Is that close to what you need?

Re: sas loop macro

RW9 — Mon, 06 Jul 2015 13:47:46 GMT

Try posting a datastep with some test data and required output as your logic isn't hard to follow. Why do you need a macro? Why not just do:

data want;

set have;

where col1 in ("aaa","bbb","ccc") or col2 in ("aaa","bbb","ccc") or col3 in ("aaa","bbb","ccc");

run;

Re: sas loop macro

jack1078 — Mon, 06 Jul 2015 13:49:37 GMT

but the 3 columns is an example actually are 24 and may be even 23 or 25

Re: sas loop macro

Tom — Mon, 06 Jul 2015 13:51:44 GMT

You should only use macro logic to generate SAS code when you cannot do what you want with the basic language.

data want ;

set have ;

array hr hour01-hour24 ;

bad=0;

do over hr ;

if hr not in ('AAA','BBB','CCC') then bad=1;

end;

if bad;

run;

Re: sas loop macro

Reeza — Mon, 06 Jul 2015 13:53:41 GMT

Use an ARRAY instead of macro loop and the WHICHC function.

If you post sample data with expected output your problem will be clearer and we can help you more.

Re: sas loop macro

jack1078 — Mon, 06 Jul 2015 13:54:40 GMT

thank's a lot, tom

you have been very useful

bie bie

Re: sas loop macro

ChrisNZ — Tue, 07 Jul 2015 11:20:32 GMT

@Jack 1078. Please mark the answer as correct if you have your answer.