Count = count+1 equivalent for String Operations

ykk — Mon, 15 Dec 2014 21:24:42 GMT

I had written the below code

msr='TEST';

count =1;

if COALESCE(NEW_GLOBAL_MIN,EXISTING_GLOBAL_MIN) eq . then

do;

msr = msr||'GLOBAL_MIN';

count = count+1;

put msr;

put 'inside 1 if';

end;

if COALESCE(NEW_GLOBAL_MEDIAN,EXISTING_GLOBAL_MEDIAN) = . then

do;

msr = msr||',GLOBAL_MEDIAN';

PUT msr;

count = count+1;

end;

if COALESCE(NEW_GLOBAL_MAX,EXISTING_GLOBAL_MAX) = . then

do;

msr = msr||',GLOBAL_MAX';

PUT msr;

count = count+1;

end;

if COALESCE(NEW_LOCAL_MIN,EXISTING_LOCAL_MIN) = . then

do;

msr = msr||'LOCAL_MIN';

PUT msr;

count = count+1;

end;

if COALESCE(NEW_LOCAL_MEDIAN,EXISTING_LOCAL_MEDIAN) = . then

do;

msr = msr||',LOCAL_MEDIAN';

PUT msr;

count = count+1;

end;

if COALESCE(NEW_LOCAL_MAX,EXISTING_LOCAL_MAX) = . then

do;

msr = msr||',LOCAL_MAX';

PUT msr;

count = count+1;

end;

put msr;

put count;

Once this is executed in the end I am expecting values 'TEST GLOBAL MIN GLOBAL MEDIAN ...'etc but I can see only TEST in the log when I print the variable msr at the end.But the value of count is 7 which confirms that all the code in the 6 if statements is executed.

Can you please help me in fixing the above issue.

Thanks

Kiran

Re: Count = count+1 equivalent for String Operations

Reeza — Mon, 15 Dec 2014 21:45:09 GMT

change the length of the Test variable at the top of your code:

length mar $20.;

msr='TEST';

.... remaining sas code

Re: Count = count+1 equivalent for String Operations

ykk — Mon, 15 Dec 2014 21:57:24 GMT

I had updated the code to use trim() while concatenating the 2 variables.I am getting the output correctly now.

topic Re: Count = count+1 equivalent for String Operations in SAS Procedures

Count = count+1 equivalent for String Operations

Re: Count = count+1 equivalent for String Operations

Re: Count = count+1 equivalent for String Operations