topic Re: question about an input statement in SAS Procedures

question about an input statement

ariel_fj — Wed, 28 Sep 2011 01:15:29 GMT

"data voter;

input Age Party : $1. (Ques1-Ques4) ($1. +1);

datalines;

23 D 1 1 2 2

45 R 5 5 4 1

67 D 2 4 3 3

39 R 4 4 4 4

19 D 2 1 2 1

75 D 3 3 2 3

57 R 4 3 4 4

Above is a part of code I quoted. What I cannot understand is the "+1" following "$1." in second line.

What is its function? If without it, what will be wrong?

Re: question about an input statement

art297 — Wed, 28 Sep 2011 01:32:42 GMT

The way it is written, yes, it is needed. Conversely, something like the following would also work:

data voter;

informat party ques1-ques4 $1.;

input Age Party Ques1-Ques4;

datalines;

23 D 1 1 2 2

45 R 5 5 4 1

67 D 2 4 3 3

39 R 4 4 4 4

19 D 2 1 2 1

75 D 3 3 2 3

57 R 4 3 4 4

;

You have a number of options and capabilities when it comes to inputting data in SAS. For a nice overview, take a look at:

http://support.sas.com/documentation/cdl/en/lrcon/62955/HTML/default/viewer.htm#a003209907.htm

Re: question about an input statement

Ksharp — Thu, 29 Sep 2011 08:11:14 GMT

Party : $1.

Means to eat a character, colon means to stop read when encounter a delimiter blank ,

Because it is list input method, so point will move a unit forward.

(Ques1-Ques4) ($1. +1);

is equal to Ques1 $1. +1 Ques2 $1. +1 Ques3 $1. +1 Ques4 $1. +1

Ksharp

Re: question about an input statement

Narendra — Fri, 30 Aug 2013 07:14:55 GMT

I have one ques..

If I am not giving +1, then it is not taking any values for Ques2 and Ques4, By Default how it is working..plz explain?

Re: question about an input statement

Doc_Duke — Fri, 30 Aug 2013 14:14:24 GMT

Narenda,

Without the +1, the blanks between the numbers are read as data. If you look carefully, you would see that the value for Ques3 is actually the value that was meant for Ques2 in the original.