topic Re: Matching year with marital status in SAS Procedures

Matching year with marital status

spg — Wed, 12 Jun 2013 18:22:18 GMT

Hi,

This follows from a question I'd posted earlier. My data looks like this, each person's purchase of a particular product at a given year...and his/her marital status over the years (Married or Divorced). I need a single column that will give me the marital status according to year of purchase. So for person 1, the STATUS should be Married, person 2 Married, person 3 Divorced etc.

How can I get at this?

Person	Year of purchase	M_2009	M_2010	M_2011	M_2012	D_2009	D_2010	D_2011	D_2012	STATUS
1	2009	1	1	0	0	0	0	1	1	Married
2	2012	1	1	1	1	0	0	0	0	Married
3	2012				0				1	Divorced
4	2011			1	0			0	1
5	2009	0	0	0	0	1	1	1	1
6	2010		0	0	0		1	1	1
7	2011		1	1			0	0

Thanks!

Re: Matching year with marital status

Reeza — Wed, 12 Jun 2013 18:36:05 GMT

Try the vvaluex function.

Re: Matching year with marital status

Astounding — Wed, 12 Jun 2013 19:42:44 GMT

Untested, but it should be working:

data want;

set have;

array marr {2009:2012} M_2009 - M_2012;

length status $ 8;

if marr{year}=1 then status='Married';

else status='Divorced';

run;

I guess if I were looking for job security, I might code this after the LENGTH statement:

status=substr('DivorcedMarried ', 1 + marr{year}*8, 8);

All the code does assume that Year is always within range, always takes on the right value, and that the Divorced/Married pairs are always the opposite of one another for any given year.

Good luck.

Re: Matching year with marital status

Reeza — Wed, 12 Jun 2013 19:56:35 GMT

data test;

set have;

Status=ifc(vvaluex("M_"||put(year_purchase, 4.))=1, "Married", "Divorced");

run;