using indexing to change contents of a SAS/IML sublist

rbettinger — Tue, 22 Jun 2021 15:14:33 GMT

I want to use indexing to change the contents of a SAS/IML sublist. I do not know if I am making syntax errors or if SAS/IML does not do what I want it to do because I am exceeding the product's design specs. Here is my code example:

proc iml ;
package load ListUtil ;

charVec = { 'abcde' 'fgh' 'ijklmn' } ;    /* define 1x3 character vector */

L_char = [ #'charVec'=charVec ] ;         /* define list comprising one item of 1x3 character entries */
call struct( L_char ) ;

temp = L_char$'charVec' ;                 /* create 1x3 character matrix from list item */
call struct( temp ) ;

do i = 1 to ncol( temp ) ; 
   print i 'temp[' i ']=' ( temp[ i ] ) ; /* print contents of temp as individual entries to demonstrate scalar addressing */
end ;

L_char =[ #'temp1'=temp ] ;               /* create new list comprising one item of 1x3 character entries */
call struct( L_char ) ;

L_char1 = L_char$'temp1'[ { 3 2 1 } ] ;   /* create new list of reversed character entries */

L_char1$('temp'[ 2 ]) = 'middle string' ; /* attempt to change contents of subitem using indexing */

call struct( L_char1 ) ;

quit

The IML interpreter generates an error when I try to index into the L_char1$'charVec' sublist:

ERROR: (execution) Invalid subscript or subscript out of range.

I do not know how to create the correct syntax to change an entry in the sublist temp1 in the list L_char1. Am I trying to do something that is not possible within IML as currently defined, or do I merely not understand the syntactic niceties?

TIA,

Ross Bettinger

Re: using indexing to change contents of a SAS/IML sublist

Rick_SAS — Tue, 22 Jun 2021 15:52:24 GMT

Pay attention to the types of the variables. You wrote

L_char1 = L_char$'temp1'[ { 3 2 1 } ] ;   /* create new list of reversed character entries */

but actually L_char1 is a character vector (so shouldn't have an L_ prefix). Thus, you can't use the $ operator on it.

The next line has several errors. There is no named item 'temp'. You can't replace part of an item; you can only replace the item. You are attempting to assign a value that is longer than the character vector can hold.

Assuming your goal is to change the second element of L_char$'temp1', you can do it like this:

c = L_char$'temp1';       /* extract item */
print (nleng(c));         /* length is only 6 */
c[2] = 'middle string' ;  /* change value (it will be truncated at 6 characters) */
L_char$'temp1' = c;       /* update item */
call struct( L_char ) ;

topic Re: using indexing to change contents of a SAS/IML sublist in SAS/IML Software and Matrix Computations

using indexing to change contents of a SAS/IML sublist

Re: using indexing to change contents of a SAS/IML sublist