Sort, if statement

Salah — Tue, 30 Mar 2021 21:00:23 GMT

Hello

I have m failure observations X_1,X_2,...,X_m. The study ends at time (T) I may observe the mth failure before time T and I may not. If the mth failure is observed after time T then I have to know its value. However, I don't know how to write that part and I really appreciate any help.

AT the same time I need to know the failure value that took place just before T and its position, i.e. the j value such that X_(j) < T < X_(j+1). For this I wrote the code below

call sortndx(idx, x, 1);

do idx=1 to m;

if (( X[idx] < T) & (X[idx+1] > T)) then j=idx;

end;

print j;

Unfortunately, I keep on getting the following error message

Re: Sort, if statement

Rick_SAS — Tue, 30 Mar 2021 21:45:25 GMT

The error message tells you that you are trying to access X[6] even though X only has 5 elements.

The problem occurs because the second part of your IF/THEN statement has the expression

X[idx+1] > T

and idx+1=6 when the loop index has the value idx=5.

I'm not sure what you are trying to accomplish with the loop, but if you want to find all elements of X that are less than T, you can use

k = loc(X<T);

if k is empty, then no failures occurred before T. If k is not empty, then X[k[ncol(k)]] is the value of the greatest time less than T.

topic Sort, if statement in SAS/IML Software and Matrix Computations

Sort, if statement

Re: Sort, if statement